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Elena L [17]
2 years ago
6

135 students attended an assembly at Piper School. The student enrollment at the school is 180. What percentage of the students

attended the assembly?
Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
8 0
We know that the total number of students is 180, so 180 is the 100 precent of the students, now we can set up a proportion and solve

180/100=135/x

x=135 times 100 over 180
x=75%
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So in a cube, the width, length, and height are the same. Therefore, you have to find the cube root of 15.625 which is 2.5 and so the side length is 2.5
6 0
3 years ago
3x−8−12x=42<br> what is x?
MA_775_DIABLO [31]

Answer:

x = -50/9    

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

3x - 8 - 12x = 42

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Combine like terms:                    -9x - 8 = 42
  2. Isolate <em>x</em> term:                              -9x = 50
  3. Isolate <em>x</em>:                                        x = -50/9          
3 0
2 years ago
Determine the equation of the line that passes through the points (-1 , 10) and (2,4)
docker41 [41]

Given:

The two points are (-1,10) and (2,4).

To find:

The equation of line which passes though the given points.

Solution:

If a line passes through two points, then the equation of line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

The line passes through (-1,10) and (2,4). So, the equation of line is

y-10=\dfrac{4-10}{2-(-1)}(x-(-1))

y-10=\dfrac{-6}{2+1}(x+1)

y-10=\dfrac{-6}{3}(x+1)

y-10=-2(x+1)

Using distributive property, we get

y-10=-2x-2

Adding 10 both sides, we get

y=-2x-2+10

y=-2x+8

Therefore, the required equation of line is y=-2x+8.

5 0
2 years ago
Yo this is for a diagnostic grade can someone help
Mnenie [13.5K]
35 people total that went on the trip.
4 0
2 years ago
Read 2 more answers
PLEASE HELP ME I ASAP<br><br>I WILL MARK YOU BRAINLIEST
kramer
<h3>Function 1 : </h3>

Observe the abscicca and ordinates

<u>*</u><u>Note</u><u> </u><u>that</u><u>:</u><u>-</u><u> </u><em>y-coordinate</em><em> </em><em>is</em><em> </em><em>ordinate</em><em> </em><em>and</em><em> </em><em>x-coordinate</em><em> </em><em>is</em><em> </em><em>abscicca</em><em>.</em>

  • The ordinate having 0 as abscicca in function 1 is (0,1), Thus.. The y-intercept is 1

<h3>Function 2 : </h3>

Observe the graph and mark the point where function meets y-axis

<u>*</u><u>Note</u><u> </u><u>that</u><u>:</u><u>-</u><u> </u><em>The</em><em> </em><em>point</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>graph</em><em> </em><em>where</em><em> </em><em>the</em><em> </em><em>function</em><em> </em><em>meets</em><em> </em><em>y-axis</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>y-intercept</em><em>.</em>

  • The point where the function meets is (0,1). Therefore, The y-intercept of function 2 is also 1

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

<em><u>Thus, Option C is the correct choice!!~</u></em>

7 0
2 years ago
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