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Elena L [17]
3 years ago
6

135 students attended an assembly at Piper School. The student enrollment at the school is 180. What percentage of the students

attended the assembly?
Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
8 0
We know that the total number of students is 180, so 180 is the 100 precent of the students, now we can set up a proportion and solve

180/100=135/x

x=135 times 100 over 180
x=75%
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Elena L [17]
This is a same side interior angle, which means that the two angles, when added, will equal 180°

y + 72 = 180

Isolate the y, subtract 72 from both sides

y + 72 (-72) = 180 (-72)

y = 180 - 72

y = 108

A) 108°, is your answer


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3 0
3 years ago
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What is a function that converts an input of letters and numbers into an encrypted output of a fixed length
nika2105 [10]

The function that converts an input of letters and numbers into an encrypted output of a fixed length is the hash function

<h3>How to determine the function?</h3>

From the question, we have the following highlights:

  • The inputs are letters and numbers
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The mathematical function with the above features is a hash function

Hence, the function is the hash function

Read more about hash at:

brainly.com/question/4478090

8 0
2 years ago
Determine the amplitude of the following graph.​
kodGreya [7K]

Answer:

amplitude = 3

Step-by-step explanation:

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5 0
2 years ago
Find the interquartile range (IQR) of the data in the dot plot below. chocolate chips 0 0 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10
Brums [2.3K]

*The dot plot is shown in the attachment below

Answer:

2

Step-by-step explanation:

Interquartile range is the difference between the upper median (Q3) and the lower median (Q1).

First, let's write out each value given in the data. Each dot represents a data point.

We have:

2, 3, 3, 4, 4, 4, 4, 5, 5, 6, 7

=>Find the median:

Our median is the middle value. The middle value is the 6th value = 4

==>Upper median Q3) = the middle value of the set of data we have from the median to our far right.

2, 3, 3, 4, 4, |4,| 4, 5, [5], 6, 7

Our upper median = 5

==>Lower median(Q1) = the middle value of the data set we have from our median to our far left.

2, 3, [3], 4, 4, |4,| 4, 5, 5, 6, 7

Lower median = 3

==>Interquartile range = Q3 - Q1 = 5-3 = 2

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3 years ago
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Nadusha1986 [10]

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10.667 yards

Step-by-step explanation:

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