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PolarNik [594]
1 year ago
11

Divide, need help again ppl, thanks!​

Mathematics
2 answers:
Kobotan [32]1 year ago
6 0

Answers:

5.) \displaystyle \pm{1\frac{2}{3}}

4.) \displaystyle 2

3.) \displaystyle \pm{1\frac{2}{3}}

2.) \displaystyle 2

1.) \displaystyle \pm{2}

Step-by-step explanations:

5.) \displaystyle \frac{\sqrt{75}}{\sqrt{27}} \hookrightarrow \sqrt{2\frac{7}{9}} \hookrightarrow \frac{\pm{5\sqrt{3}}}{\pm{3\sqrt{3}}} \\ \\ \boxed{\pm{1\frac{2}{3}}}

4.) \displaystyle \frac{\sqrt[5]{96}}{\sqrt[5]{3}} \hookrightarrow \sqrt[5]{32} \hookrightarrow \frac{2\sqrt[5]{3}}{\sqrt[5]{3}} \\ \\ \boxed{2}

3.) \displaystyle \frac{\sqrt{125}}{\sqrt{45}} \hookrightarrow \sqrt{2\frac{7}{9}} \hookrightarrow \frac{\pm{5\sqrt{5}}}{\pm{3\sqrt{5}}} \\ \\ \boxed{\pm{1\frac{2}{3}}}

2.) \displaystyle \frac{\sqrt[3]{24}}{\sqrt[3]{3}} \hookrightarrow \sqrt[3]{8} \hookrightarrow \frac{2\sqrt[3]{3}}{\sqrt[3]{3}} \\ \\ \boxed{2}

1.) \displaystyle \frac{\sqrt{8}}{\sqrt{2}} \hookrightarrow \sqrt{4} \hookrightarrow \frac{\pm{2\sqrt{2}}}{\pm{\sqrt{2}}} \\ \\ \boxed{\pm{2}}

I am joyous to assist you at any time.

7nadin3 [17]1 year ago
4 0

Answer:

<h2>√2,2√4</h2>

Step-by-step explanation:

<h2>√2,√8</h2><h2>√2,√4×2</h2><h2>√2,√2×2×2</h2><h2>√2,√2×2 2</h2><h2>√2,2√4 answer</h2>
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