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Schach [20]
3 years ago
10

While working on a forty-slide PowerPoint presentation, a user needs to quickly look over the six slides that have orange backgr

ounds. How can the user most efficiently find the six slides and then see them in the main PowerPoint window?​
Computers and Technology
1 answer:
guapka [62]3 years ago
8 0

Answer:

B

Explanation:

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How many answers do you need to be able to write messages on here??
Kipish [7]

1,000

Hope this helps!



~Courtney

3 0
3 years ago
2. Sometimes, validating the HTML code for a web page will help you debug an application, because a. the page won’t run in a bro
aleksandrvk [35]

Answer:

Option c. you can be sure that a validated page will work correctly in a browser

Explanation:

A faulty HTML codes can result in various types of unexpected error when running the web page in different platforms or browsers. This will cause an inconsistent style or layout. HTML code validation can check if the code adopt the standard tag and structure. A validated HTML code can guarantee a web application running smoothly in different browsers and always present consistent web page layout to users. HTML code validation has become part of the standard workflow before a web page go live in internet.

4 0
3 years ago
Find the root using bisection method with initials 1 and 2 for function 0.005(e^(2x))cos(x) in matlab and error 1e-10?
frutty [35]

Answer:

The root is:

c=1.5708

Explanation:

Use this script in Matlab:

-------------------------------------------------------------------------------------

function  [c, err, yc] = bisect (f, a, b, delta)

% f the function introduce as n anonymous function

%       - a y b are the initial and the final value respectively

%       - delta is the tolerance or error.

%           - c is the root

%       - yc = f(c)

%        - err is the stimated error for  c

ya = feval(f, a);

yb = feval(f, b);

if  ya*yb > 0, return, end

max1 = 1 + round((log(b-a) - log(delta)) / log(2));

for  k = 1:max1

c = (a + b) / 2;

yc = feval(f, c);

if  yc == 0

 a = c;

 b = c;

elseif  yb*yc > 0

 b = c;

 yb = yc;

else

 a = c;

 ya = yc;

end

if  b-a < delta, break, end

end

c = (a + b) / 2;

err = abs(b - a);

yc = feval(f, c);

-------------------------------------------------------------------------------------

Enter the function in matlab like this:

f= @(x) 0.005*(exp(2*x)*cos(x))

You should get this result:

f =

 function_handle with value:

   @(x)0.005*(exp(2*x)*cos(x))

Now run the code like this:

[c, err, yc] = bisect (f, 1, 2, 1e-10)

You should get this result:

c =

   1.5708

err =

  5.8208e-11

yc =

 -3.0708e-12

In addition, you can use the plot function to verify your results:

fplot(f,[1,2])

grid on

5 0
3 years ago
A computer understand..............codes.<br>​
KiRa [710]

Answer:Computers only understand machine code - they do not understand high-level language code. Any high-level programming language code has to be converted to executable code. Executable code is also known as machine code which is a combination of binary code 0s and 1s.

Explanation:

6 0
3 years ago
Which loan type requires you to make loan payments while you’re attending school?
Levart [38]
<span>A:Unsubsidized federal loan</span>
7 0
4 years ago
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