Answer:
TreeNode minimum(TreeNode root) {
if (root != null) {
if (firstChild == null && nextSibling == null) {
return root;
} else {
TreeNode begin = minimum(root.firstChild);
TreeNode last = minimum(root.nextSibling);
if (begin == false && (last == false || begin.data < last.data)) {
return begin;
} else {
return last;
}
} else {
return null;
}
}
Explanation:
The Java program defines a recursive method called minimum that calls itself twice with the first and last leaf of the treenode as the respective arguments. and returns the minimum value of the treenode if the root argument is not undefined.
Answer:
B. color and painting tools
Explanation:
As for this problem, taking into consideration the options presented is critical and that it has to be identified. The most probable and the most likely answer to be the correct one is C. Once e-mail is sent out, it cannot be taken back.
In some cases, e-mails can fail to be sent to the receiver of the mail due to some factors such as the internet connection of the sender, the amount of information it currently holds, and so on and so forth. There might have already been solutions for this that come in forms of applications, extensions, and the like, but once the e-mail is sent, it cannot be taken back.
Music = (“rap”, “hip hop”, “gospel”)
Country = (“country”,) #make sure that comma is outside of quotes
New_music = music + Country
print(New_music)
#var can be whatever you want
output:
(“rap”, “hip hop”, “gospel”, “country”)
Idk what programming language you use so
private int quarter_num(int num) {
return num / 4;
}
