Answer:
1. 
2. ![x=\pm7i[tex]3.[tex]\pm 12x =a](https://tex.z-dn.net/?f=x%3D%5Cpm7i%5Btex%5D%3C%2Fp%3E%3Cp%3E3.%5Btex%5D%5Cpm%2012x%20%3Da)
4. 22
Step-by-step explanation:
1. 



2. 


![x=\pm7i[tex]3. Area of square = [tex]a^{2}](https://tex.z-dn.net/?f=x%3D%5Cpm7i%5Btex%5D%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3E3.%20Area%20of%20square%20%3D%20%5Btex%5Da%5E%7B2%7D)
Where a is the side
We are given an area o square = 
So, 


4. We are given that the solution of quadratic equation -9 and 9
So, equation becomes:


So, in the given equation 
z should be the number from which if we subtract 103 so we get 81
Substitute z = 22



Thus the value of z is 22
use brainly to find the answer
Answer:
2304
Step-by-step explanation:
<u>Given :- </u>
- A geometric sequence is given to us which is 9 , -18 , 36.
And we need to find out the 9th term of the sequence. Here firstly we should find the Common Ratio and then we can substitute the respective values in the formula to find the nth term of a geometric sequence .
<u>Common Ratio :- </u>
CR = -18÷ 9 = -2
<u>The </u><u>9</u><u> th term :- </u>
T_n = arⁿ - ¹
T_9 = 9× (-2) ⁹ - ¹
T_9 = 9 × (-2)⁸
T_9 = 9 × 256
T_9 = 2304
<u>Hence the 10th term is </u><u>2</u><u>3</u><u>0</u><u>4</u><u>.</u>
1 out of 52. So 1/52 equals some decimal. Plug in calc.
2.1 x 82 =
172.2
I hope this answer was helpful! :)