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2 years ago

13

Write an equation of the parabola with the vertex (-5,4) and focus (-5,0)

1 answer:

ch4aika [34]2 years ago

5 0

Answer:

-0.4 or -10.4

Step-by-step explanation:

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Solve the right triangle. Round decimal answers to the nearest tenth.

dem82 [27]

Step-by-step explanation:

RS = 15/ tan57° = 9.7

RT = 15/sin57° = 17.9

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3 years ago

6. In both Mr. Jacquez's Math 2 classes, Period 2 and Period 3 were given the same test. The table below shows the results from

umka2103 [35]

Answer: pass 12 fail 12 passes 15 fail1 3

Step-by-step explanation:

pass 12 fail 12

pass 15 fail 13

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2 years ago

What is the rule for finding the sum of two negative integers

ArbitrLikvidat [17]

adding two negative integers always yields a negative sum

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3 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

At 5 a.m., the temperature at an airport was −9.4°F . Six hours later, the temperature was 2.8°F . Which expression represents t

guajiro [1.7K]

-9.4 + x6 = 2.8 this is an equation for the question

7 0

2 years ago

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