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Lesechka [4]
2 years ago
8

Forty is what percent of 50? worth 11 pts.

Mathematics
2 answers:
a_sh-v [17]2 years ago
4 0
The answer is 20! 40% x 50
 (40/100)x50= 20
RoseWind [281]2 years ago
3 0
The answer is 40 is 80% of 50 ☺
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A ball is thrown in the air from a ledge. Its height in feet is represented by
Strike441 [17]
D.6 is your answer
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4 0
3 years ago
1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x
qaws [65]

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is (2x+10)^\circ, so the measure of arc DF is

m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ

The inscribed angle theorem tells us that the central angle subtended by arc DF, \angle DOF, has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

m\angle DOF=2m\angle OEF=64^\circ

so the measure of arc DF is also 64 degrees. So we have

170-2x=64\implies106=2x\implies\boxed{x=53}

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

m\angle EFO+m\angle FEO+m\angle EOF=180^\circ\implies\boxed{m\angle EFO=62^\circ}

7 0
2 years ago
Solve For Each Variable.
bixtya [17]

The first equation given 6=1-2n+5

We have to add 1 and 5 to the right side first. We will get,

6= 6 - 2n

To get rid of 6 from the right side we have to subtract 6 from both sides.

6-6 = 6-6-2n

6-6 = -2n

0=-2n

To find n we have to move -2 to the other side by dividing both side by -2.

0/-2 = -2n/-2

0= n

n=0

So we have got the required answer for the first question.

The solution is n = 0.

The second equation given,

8x-2 = -9+7x

First we have to move 7x to the left side by subtracting it from both sides.

8x-7x-2 = -9+7x-7x

8x-7x-2 = -9

x-2 = -9

Now we have to move -2 to the right side by adding 2 to both sides.

x-2+2 = -9+2

x = -9+2

x = -7

We have got the required answer for the second question.

The solution is x = -7.

The third equation given,

-8 = -(x+4)

We have to get rid of that negative sign from both sides. As we have negative sign to both sides we can cancel it out. We will get,

8=x+4

Now we have to move 4 to left side by subtracting it from both sides.

8-4 = x+4-4

8-4 = x

4=x

x = 4

So we have got the required answer .

The solution is x = 4.

3 0
2 years ago
Someone help me please
Rainbow [258]

Answer:

B

Step-by-step explanation:


5 0
3 years ago
Using Triangle Similarity Theorems (6)
Fantom [35]

Answer:

DC = 3

Step-by-step explanation:

Based on triangle similarity theorem, we would have the following equation:

\frac{AD}{AC} = \frac{AE}{AB}

Plug in the values

\frac{9}{9 + DC} = \frac{12}{12 + 4}

\frac{9}{9 + DC} = \frac{12}{16}

\frac{9}{9 + DC} = \frac{3}{4}

Cross multiply

3(9 + DC) = 9×4

27 + 3DC = 36

Subtract 27 from each side

3DC = 36 - 27

3DC = 9

Divide both sides by 3

DC = 9/3

DC = 3

6 0
2 years ago
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