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snow_lady [41]
3 years ago
8

A golf cart travels 12 ft in 6 seconds at that speed how far can the golf Cart go in 13 seconds

Mathematics
1 answer:
baherus [9]3 years ago
3 0

Answer:

26

Step-by-step explanation:

12 ft in 6 sec means it goes two feet per second so it would be 12 plus 12 plus 2 which is 26 ft in 13 sec

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You can buy 26 movies
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HELP<br> If you don’t know it then please don’t answer.
vovangra [49]

the answer is 4.8. Your welcome

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Every one reading this please help! I don't understand this and I will give brainliest to the person that helps first with a goo
stira [4]
Since the area of the poster doesn't change by putting it in a frame, we presume the question is asking what the area of the framed poster is.

The length of the poster in its frame is ...
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6 0
3 years ago
Read 2 more answers
Mario has a business selling muffins. Let x be the price of a muffin. Then, the profit P for Mario’s business is given by p(x)=-
Rufina [12.5K]
To make a positive profit p(x)>0 we need to make:
-100 x^{2} +350x-150 \ \textgreater \  0

Now we solve this for x:
-2 x^{2} +7x-3 \ \textgreater \ 0

We have:
a = -2
b = 7
c = -3

We will use formula for quadratic equation:
x_{1} =  \frac{-b+ \sqrt{ b^{2}-4ac } }{2a}  \\  \\  x_{2} =  \frac{-b- \sqrt{ b^{2}-4ac } }{2a}  \\  \\  x_{1} =  \frac{-7+ \sqrt{ 49-24 } }{-4} = \frac{-7+5 }{-4} = \frac{-2 }{-4} = \frac{1}{2}  \\  \\  x_{2} =  \frac{-7- \sqrt{ 49-24 } }{-4}  = \frac{-7-5 }{-4} = \frac{-12 }{-4} = 3

We got two solutions. One is fraction other is whole number. We will not consider fraction because the amount of muffins sold must be whole number. So our solution is:
x>3
5 0
3 years ago
Read 2 more answers
More on Areas. Farmer Jones, and his wife, Dr. Jones, both mathematicians, decide to build a fence in their field to keep the sh
Olin [163]

Answer:

Area covered by the fences will be 16.1 unit²

Step-by-step explanation:

Let the first parabola is represented by the function f(x) = 6x²

and second parabola by g(x) = x² + 9

point of intersection of the graphs will be determined when f(x) = g(x)

6x² = x² + 9

5x² = 9

x² = 1.8

x = ± 1.34

Now we will find the area between these curves drawn on the graph.

Area = \int_{-1.34}^{1.34}[f(x)-g(x)]dx=\int_{-1.34}^{1.34}[6x^{2}-(x^{2}+9)]dx

= \int_{-1.34}^{1.34}(5x^{2}-9)dx

= [\frac{5}{3}x^{3}-9x]_{-1.34}^{1.34}

= [\frac{5}{3}(-1.34)^{3}-9(-1.34)-\frac{5}{3}(1.34)^{3}+9(1.34)]

= [-4.01+12.06-4.01+12.06]

= 16.1 unit²

6 0
3 years ago
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