What is it that I am supposed to be doing?
<span>5/ 8 x 4/ 5
=20/40
=1/2
answer is </span>A. 1/2
14 and 11
let x be the second number then the first number = x + 3 ( 3 more than second)
Also 3(x + 3) = 5x - 13
3x + 9 = 5x - 13
subtract 3x from both sides
9 = 5x - 3x - 13
9 = 2x - 13
add 13 to both sides
22 = 2x
divide both sides by 2
11 = x → second number
first number = x + 3 = 11 + 3 = 14
<h2><em>y
2
+
6
y
−
16
=
(
y
+
8
)
(
y
−
2
)
</em></h2><h2 /><h2><em>Explanation:
</em></h2><h2><em>Note that in general:
</em></h2><h2 /><h2><em>(
y
+
a
)
(y
−
b
)
=
y
2
+
(
a
−
b
)
y
−
a
b
</em></h2><h2 /><h2><em>So we want to find a pair of factors a and b of 16 which differ by 6
. </em></h2><h2><em>The pair 8
,
2 works in that 8−
2
=
6 and 8
⋅
2=
16
.
</em></h2><h2 /><h2><em>Hence:
</em></h2><h2><em>
y
2
+
6
y
−
16
=
(
y+
8
)
(
y
−
2
)</em></h2><h2><em>y=2,-8</em></h2>
Here, we want to check for the relationship between the image and its pre-image
The pre-image is (x,y)
The image is (3x,3y+5)
As we can see, the pre-image is not similar
This is because the transformation applied to the two values are not same
Thus, we have that;
No, the image is not similar to the pre-image as the translations applied to both coordinates are not same
The pre-image was transformed by dilating the x-coordinate of the pre-image by 3 units while the y-coordinate was transformed by dilating the y-coordinate of the pre-image by 3 and translating it upward by 5 units
