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Fed [463]
2 years ago
12

Solve this quadratic equation using the quadratic formula. 3x 2 + 5x + 1 = 0

Mathematics
1 answer:
Tju [1.3M]2 years ago
8 0

Answer:

x=\frac{-\sqrt{13} -5}{6} or x=\frac{\sqrt{13} -5}{6}

Step-by-step explanation:

The given quadratic equation is

3x^2+5x+1=0


When we compare to the general quadratic equation,

ax^2+bx+c=0, then we have


a=3,b=5,c=1


The quadratic formula is given by,

x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}


We substitute the given values into the formula to obtain,

x=\frac{-5\pm \sqrt{5^2-4(3)(1)} }{2(3)}


This simplifies to,

x=\frac{-5\pm \sqrt{25-12} }{2(3)}


This further simplifies to,

x=\frac{-5\pm \sqrt{13} }{6}


We split the plus or minus sign to obtain,


x=\frac{-\sqrt{13} -5}{6} or x=\frac{\sqrt{13} -5}{6}








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