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steposvetlana [31]
3 years ago
9

The slope of the line below is 2/5 and the y-intercept is 4 . What is the slope intercept equation of the line ?

Mathematics
2 answers:
alekssr [168]3 years ago
5 0
The answer is (9,2) so i just saved you from a very boring and long explanation your welcome
Grace [21]3 years ago
4 0
Y=2/5X+4 is the slope-intercept form. 

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What the hypothenuse of a right with length of 6 and 8
Aloiza [94]
This is a pythagorean triple --> 3-4-5
Although you notice it is doubled but with the same pattern --> 6-8-10

Thus, the hypotenuse is 10. 
8 0
3 years ago
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What is 2(3x + 12y - 5 - 17x - 16y +4) simplified?
fiasKO [112]

Answer:

<h2>2(-14x-4y-1) / -28x-8y-2</h2>

Step-by-step explanation:

2(3x + 12y - 5 - 17x - 16y +4)

the 2 outside the bracket means we need to multiply everything by 2

=

6x+24y-10-34x-32y+8

now put all the like-terms together

6x-34x+24y-32y+8-10

now add them together

=-28x-8y-2

now find the HCF

2

put 2 outside the bracket and then divide every number by 2

2(-14x-4y-1)

this is as simplified it can get

5 0
3 years ago
Write ✓-6 in simplest radical form.
inn [45]
It is: i √6 i believe :))
7 0
3 years ago
PLEASE HELP ME!!!!!!!!!! 57-4t &gt;(their is an egual sign under the less then sign)13
Alexandra [31]
57 - 4t > = 13.....subtract 57 from both sides
-4t > = 13 - 57
-4t > = - 44 ...divide both sides by -4, and change the inequality sign
t < = -44 / -4
t < = 11

u solve inequalities much like u do equations except for one very important rule. In an inequality, if u divide/multiply by a negative number, u have to change the inequality sign.



8 0
3 years ago
Read 2 more answers
If A^2=A, which matrix is matrix A
Ronch [10]

Consider all options:

A.

\left[\begin{array}{cc}5&5\\-4&-4\end{array}\right] \cdot \left[\begin{array}{cc}5&5\\-4&-4\end{array}\right] =\left[\begin{array}{cc}5\cdot 5+5\cdot (-4)&5\cdot 5+5\cdot (-4)\\-4\cdot 5+(-4)\cdot (-4)&-4\cdot 5+(-4)\cdot (-4)\end{array}\right]=

=\left[\begin{array}{cc}5&5\\-4&-4\end{array}\right].

This option is true.

B.

\left[\begin{array}{cc}6&5\\5&6\end{array}\right] \cdot \left[\begin{array}{cc}6&5\\5&6\end{array}\right] =\left[\begin{array}{cc}6\cdot 6+5\cdot 5&6\cdot 5+5\cdot 6\\5\cdot 6+6\cdot 5&5\cdot 5+6\cdot 6\end{array}\right]=

=\left[\begin{array}{cc}61&60\\60&61\end{array}\right].

This option is false.

C.

\left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right] \cdot \left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right] =\left[\begin{array}{cc}0.5\cdot 0.5+(-0.5)\cdot (-0.5)&0.5\cdot (-0.5)+(-0.5)\cdot 0.5\\-0.5\cdot 0.5+0.5\cdot (-0.5)&-0.5\cdot (-0.5)+0.5\cdot 0.5\end{array}\right]=

=\left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right].

This option is true.

D.

\left[\begin{array}{cc}0.5&0.5\\-0.5&0.5\end{array}\right] \cdot \left[\begin{array}{cc}0.5&0.5\\-0.5&0.5\end{array}\right] =\left[\begin{array}{cc}0.5\cdot 0.5+0.5\cdot (-0.5)&0.5\cdot 0.5+0.5\cdot 0.5\\-0.5\cdot 0.5+0.5\cdot (-0.5)&-0.5\cdot 0.5+0.5\cdot 0.5\end{array}\right]=

=\left[\begin{array}{cc}0&0.5\\-0.5&0\end{array}\right].

This option is false.

E.

\left[\begin{array}{cc}-6&-6\\5&5\end{array}\right] \cdot \left[\begin{array}{cc}-6&-6\\5&5\end{array}\right] =\left[\begin{array}{cc}-6\cdot (-6)+(-6)\cdot 5&-6\cdot (-6)+(-6)\cdot 5\\5\cdot (-6)+5\cdot 5&5\cdot (-6)+5\cdot 5\end{array}\right]=

=\left[\begin{array}{cc}6&6\\-5&-5\end{array}\right].

This option is false.

Answer: correct options are A and C.

8 0
3 years ago
Read 2 more answers
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