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3 years ago

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There are three people in the same room, and we are curious whether two of them have their birthday in the same month

1 answer:

Studentka2010 [4]3 years ago

4 0

For the answer to the question above, first all you have to do is have a confidence. If you are curious about their birthday's come up with a question that won't sound so weird. Like " Hi, I'm doing a research for a subject about people who are born on the same month can you help me? or something like that.
All you have to do is have some confidence so that you wouldn't sound so weird

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I’ll give brainliest

nirvana33 [79]

1. 90 x 133 = 11970/100 = 119.7
0.9 x 133 = 119.7
Yes

3 0

3 years ago

Five basketball players try to make as many points as possible in each game. They have a mean of 12 points per game. If the firs

Alex73 [517]

I believe it's 12 points if I'm wrong I'm sorry hope this helps

6 0

3 years ago

Read 2 more answers

The coordinates of A, B, and C in the diagram are A(p,4), B(6,1), and C(9,q). Which equation correctly relates p and q?

Temka [501]

ANSWER

$p + q= 7$

EXPLANATION

We determine the slope of each line using the slope formula;

$m = \frac{y_2-y_1}{x_2-x_1}$

The slope of BC is

$= \frac{ q - 1}{9 - 6}$

$\frac{ q - 1}{3}$

The slope of AB is

$= \frac{1 - 4}{6 - p}$

$= - \frac{3}{6 - p}$

The two lines are perpendicular so the product of their slopes is -1.

$- \frac{3}{6 - p} \times \frac{ q - 1}{3} = - 1$

This implies that,

$\frac{q - 1}{6 - p} = 1$

$q - 1=6 - p$

$q + p = 6 + 1$

$p + q= 7$

.

4 0

3 years ago

Read 2 more answers

Calculate the current in an Inductor if the energy stored is 240J and the Inductance is 24H.

SCORPION-xisa [38]

Answer:

Current, I = 4.47 Amperes.

Step-by-step explanation:

Given the following data;

Inductance = 24H

Energy stored, Eind = 240J

To find the current;

The energy stored in an inductor is given by the formula;

Eind = ½LI²

240 = ½*24*I²

Cross-multiplying, we have;

480 = 24I²

I² = 480/24

I² = 20

Taking the square root of both sides, we have;

Current, I = 4.47 Amp

6 0

3 years ago

Can someone please help me, this is for summer school and I need fast replies, I have 29 other question like these, please help.

Yuri [45]

$\implies {\blue {\boxed {\boxed {\purple {\sf { \: A. \:- 8 {v}^{4} + 3 {v}^{3} + v + 5}}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

$(4 + 6v + 3 {v}^{3} ) - (5v + 8 {v}^{4} - 1)$

➼ $\: 4 + 6v + 3 {v}^{3} - 5v - 8 {v}^{4} + 1$

Combining like terms, we have

➼ $\: - 8 {v}^{4} + 3 {v}^{3} + 6v - 5v + 4 + 1$

➼ $\: - 8 {v}^{4} + 3 {v}^{3} + v + 5$

<h3 />

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}$

7 0

3 years ago