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Eva8 [605]
3 years ago
14

There are three people in the same room, and we are curious whether two of them have their birthday in the same month

Mathematics
1 answer:
Studentka2010 [4]3 years ago
4 0
For the answer to the question above, first all you have to do is have a confidence. If you are curious about their birthday's come up with a question that won't sound so weird. Like " Hi, I'm doing a research for a subject about people who are born on the same month can you help me? or something like that.
All you have to do is have some confidence so that you wouldn't sound so weird
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-3(u+2)=5u-1+5(2u+1)
Mazyrski [523]

Answer:

u = -5/9

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

-3(u + 2) = 5u - 1 + 5(2u + 1)

<u>Step 2: Solve for </u><em><u>u</u></em>

  1. Distribute:                             -3u - 6 = 5u - 1 + 10u + 5
  2. Combine like terms:             -3u - 6 = 15u + 4
  3. Add 3u to both sides:          -6 = 18u + 4
  4. Subtract 4 on both sides:    -10 = 18u
  5. Divide 18 on both sides:      -10/18 = u
  6. Simplify:                                -5/9 = u
  7. Rewrite:                                 u = -5/9

<u>Step 3: Check</u>

<em>Plug in u into the original equation to verify it's a solution.</em>

  1. Substitute in <em>u</em>:                     -3(-5/9 + 2) = 5(-5/9) - 1 + 5(2(-5/9) + 1)
  2. Multiply:                                -3(-5/9 + 2) = -25/9 - 1 + 5(-10/9 + 1)
  3. Add:                                      -3(13/9) = -25/9 - 1 + 5(-1/9)
  4. Multiply:                                -13/3 = -25/9 - 1 - 5/9
  5. Subtract:                               -13/3 = -34/9 - 5/9
  6. Subtract:                               -13/3 = -13/3

Here we see that -13/3 does indeed equal -13/3.

∴ u = -5/9 is a solution of the equation.

3 0
3 years ago
Read 2 more answers
A broken calculator can double any number or permute its digits (but 0 cannot go up front). Can we start with number 1 and obtai
stira [4]

Answer: it's impossible to obtain 78

Step-by-step explanation: Since the calculator can double any number or permute its digits except 0 

starting with number 1 

1, 2, 4, 8, 16, 32, 64, 128

Therefore, it's impossible to obtain 78 by a series of these operations

8 0
2 years ago
An arena is hosting a concert. At the most, the arena can hold 8,500 people. If tickets have already been sold to 6,900 people,
ElenaW [278]

Answer:

Subtract 6,900 from 8,500 to get the highest number of tickets that can still be sold which is 1,600.

8 0
2 years ago
Solve the system below using an appropriate method.
fiasKO [112]
Using substitution:
4x+2y=12
y=8x+1

4x+2(8x+1)=12

distribute
4x+16x+2=12

combine like terms
18x+2=12

subtract 2 from both sides
20x=10

divide each side by 20
x=10/20

reduce
x=1/2

plug in x for the y= equation
y=8(1/2)+1

multiply
y=4+1

add
y=5

answer:
(1/2,5)
5 0
2 years ago
1 + 5sin^2x= 7sin^2x solve trig equation. Can you show me how to solve this trig equation?
pantera1 [17]

Answer: x = \frac{\pi}{4}\pm k\frac{\pi}{2}\,\,\,\,\,\,k=\{0,1,2,...\}

Step by step:

1 + 5\sin^2x= 7\sin^2x\\\sin^2 x\rightarrow z\\1 + 5z = 7z\\2z = 1\\z = \frac{1}{2}\implies \sin^2 x = \frac{1}{2}\\|\sin x| = \frac{1}{\sqrt{2}}\\\sin x = \pm\frac{1}{\sqrt{2}}=\pm\frac{\sqrt{2}}{2}\\\implies x = \frac{\pi}{4}\pm k\frac{\pi}{2}\,\,\,\,\,\,k=\{0,1,2,...\}

(Used a table of common angles)

8 0
3 years ago
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