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xeze [42]
3 years ago
13

Please help me (Just to inform you I took this once and D is not the correct answer) I’ll give brainalist + points

Mathematics
2 answers:
pochemuha3 years ago
8 0

Answer:c

Step-by-step explanation:

Monica [59]3 years ago
8 0
The answer is C

Explanation
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Which of the following factors influences a consumer when deciding to buy a
OlgaM077 [116]

Answer:

c.

Step-by-step explanation:

4 0
3 years ago
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Derive a formula to find the perimeter of an isosceles triangle in which one of the equal
Scorpion4ik [409]

Given :

Length of one of the equal sides of an isosceles triangle = 3x+2

Then, length of the other equal side will also be = 3x+2

Length of the unequal side of this isosceles triangle = 14

Formula for finding the perimeter of an isosceles triangle :

= \tt  side + side + side

A formula for finding the perimeter of this isosceles triangle :

= \tt3x + 2 + 3x + 2 + 14

Bringing all like terms together we get :

=\tt 3x + 3x + 2 + 2 + 14

= \tt6x + 4 + 14

\color{plum}\tt  = 6x + 18

Thus, the formula = 6x+18

Therefore, a formula to find the perimeter of this isosceles triangle = <u>6x+18</u>

7 0
3 years ago
HELP ME PLS &amp; FAST!!
lukranit [14]

There are 6 outcomes for the cube and 4 for the spinner. So you can multiply 6 and 4. That gives you 24. The answer is C. 24. Hope this helps!

8 0
3 years ago
Orlando bought a pair of shoes that was on sale for $30 off. The original price of the shoes was $112. What was the sale price o
d1i1m1o1n [39]
The answer is 16 can you give me brainliest ?
3 0
3 years ago
If
baherus [9]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = \frac{\sqrt3}{2}

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}

Proof LHS → RHS:

LHS                          cos 165

Double-Angle:        cos (2 · 165) = 2 cos² 165 - 1

                             ⇒ cos 330 = 2 cos² 165 - 1

                             ⇒ 2 cos² 165  = cos 330 + 1

Given:                        2 \cos^2 165  = \dfrac{\sqrt3}{2} + 1

                              \rightarrow 2 \cos^2 165  = \dfrac{\sqrt3}{2} + \dfrac{2}{2}

Divide by 2:               \cos^2 165  = \dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \dfrac{2\sqrt3+4}{8}

Square root:             \sqrt{\cos^2 165}  = \sqrt{\dfrac{4+2\sqrt3}{8}}

Scratchwork:            \cos^2 165  = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2

                             \rightarrow \cos 165  = \pm \dfrac{\sqrt3+1}{2\sqrt2}

             Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

                             \rightarrow \cos 165  = - \dfrac{\sqrt3+1}{2\sqrt2}

LHS = RHS \checkmark

4 0
4 years ago
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