(3x + 4)³ = 2197
Taking the cube root in this case is easier, although we can do it the extended way which is complicated.
![\sqrt[3]{(3x+4)^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%283x%2B4%29%5E3%7D%20)
=
![\sqrt[3]{2197}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B2197%7D%20)
3x + 4 = 13
Now solve normally.
subtract 4
3x + 4 = 13
-4 -4
3x = 9
Divide by 3 to isolate 3

3 and 3 cancels out
x = 3
Answer:
Step-by-step explanation:
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Answer: friend?...
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Answer:Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:
y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5
To try to discard one of them, let us use the vertex, which is at x = -2.
With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.
Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.
Step-by-step explanation: