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3 years ago

For normally distributed data, what proportion of observations have z-scores satisfying the following conditions:

1 answer:

6 0

From standard tables for normal distribution,
P(z<=0.62) = 0.7324
P(z<=2.92) = 0.9983

Therefore
P(0.62 < z <2.92) = 0.9983 - 0.7324 = 0.2659

The required proportion is 0.2659 or 26.6%

Answer: 0.266 or 26.6%

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Write an exponential model given the points ( 7, 12 ) and ( 8, 25 ). Round to the nearest hundredth.

inna [77]

Answer:

The exponential model is $y = 0.07\cdot e^{0.73\cdot x}$ .

Step-by-step explanation:

The exponential model can be modelled by the following mathematical expression:

$y = A\cdot e^{B\cdot x}$ (1)

Where:

$x$ - Independent variable.

$y$ - Dependent variable.

$A, B$ - Coefficients.

If we know that $(x_{1}, y_{1}) = (7,12)$ and $(x_{2}, y_{2}) = (8,25)$ , then we get the following system of equations:

$A\cdot e^{7\cdot B} = 12$ (2)

$A\cdot e^{8\cdot B} = 25$ (3)

If we divide (3) by (2), we calculate the value of $B$ :

$e^{B}=\frac{25}{12}$

$B = \ln \frac{25}{12}$

$B \approx 0.734$

And by (2), we determine the value of $A$ :

$A = 12\cdot e^{-7\cdot B}$

$A = 0.0704$

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