It has 97 amounts.
43,44,45,46,47,48,49,50,
51,52,53,54,55,56,57,58,59,60
61,62,63,64,65,66,67,68,69,70 71,72,73,74,75,76,77,78,79,80
81,82,83,84,85,86,87,88,89,90
91,92,93,94,95,96,97,98,99,100
101,102,103,104,105,106,107,108,109,110
111,112,113,114,115,116,117,118,119,120
121,122,123,124,125,126,127,128,129,
130
131,132,133,134,135,136,137,138,139
Numbers between 42-140
The question in the picture is very different from the question before the picture.
Half of 12 is ____
is a different question than
12 is ____ halves
When you say, "Halves of 12, 10, ..." it looks like you're asking the first version.
One of something is 2 halves. That is, the number of halves is exactly two times the number of "somethings." Hopefully, you can multiply each of these numbers by 2.
12*2 = 24
10*2 = 10
13*2 = 26
15*2 = 30
8*2 = 16
5*2 = 10
Im gonna assume you mean 6 - (1/3)x = -1. Your notation is not super clear. If so, solution is as follows:
6 - (1/3)x = -1 [subtract 6 from both sides]
-(1/3)x = -7 [multiply both sides by -3]
x = 21
Answer:
yes it is possible for two different numbers to eventually have the same result
Step-by-step explanation:
its basically like saying five times 2 which is 10 and 2 times 5 which is also 10 its different numbers but same outcome