What standard deviation below the mean of normal young adults equals osteoporosis?

1 answer:

8 0

The standard deviation from the mean of a young (30-year old) adult is called a t-score.
If the t-score is -1, it means that the bone density is 1 standard deviation below the mean.
It is generally considered a t-score between -1 and -2.5 low bone density.
Patients with t-scores below -2.5 (e.g. -3) is considered suffering from osteoporosis. Also, patients within this range AND suffered from one or more fractures is considered established osteoporosis.

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A flying carpet flies 2.4 miles with the wind in the same amount of time it flies 1.4 miles against the wind. The wind speed is

Ainat [17]

Answer:

$15.2~mph$

Step-by-step explanation:

Let the time flown by the flying carpet be $t$ . Then, we have that $(2.4)/t=(1.4)/t+2*4$ .

We multiply both sides of the equation by $t$ to get $2.4=1.4+8t$ .

We subtract $1.4$ from both sides to get $1=8t$ .

We divide both sides of the equation by $t=1/8$ .

We know that the speed of the flying carpet in still wind is the average of the rates of the speed of the flying carpet with the wind and against the wind.

The speed with wind is $(2.4)/(1/8)=19.2$ mph.