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3 years ago

What standard deviation below the mean of normal young adults equals osteoporosis?

1 answer:

8 0

The standard deviation from the mean of a young (30-year old) adult is called a t-score.
If the t-score is -1, it means that the bone density is 1 standard deviation below the mean.
It is generally considered a t-score between -1 and -2.5 low bone density.
Patients with t-scores below -2.5 (e.g. -3) is considered suffering from osteoporosis. Also, patients within this range AND suffered from one or more fractures is considered established osteoporosis.

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a rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1

AleksandrR [38]

Graph images undergo transformations, one of the types of transformations are rotations.
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3 years ago

Read 2 more answers

Find the greatest common factor of 24, 64, 108.

Ainat [17]

Answer:

The answer is 4.

Step-by-step explanation:

To find the greatest common factor (GCF), start by listing the factors of each number.

For 24: 1, 2, 3, 4, 6, 8, 12, 24

For 64: 1, 2, 4, 8, 16, 32, 64

For 108: 1, 2, 3, 4, 6, 9, 12, 18

Since all the factors are now written out, we can find the greatest common factor between 24, 64, and 108, and the GCF is 4.

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3 years ago

Write that down the equation for the lines that is the graphs are depicted below

erastovalidia [21]

A(1,2)

Find slope of line (m)

$\\ \sf\longmapsto m=\dfrac{2-0}{1-0}$

$\\ \sf\longmapsto m=2$

Putting in y=mx+b

$\\ \sf\longmapsto y=mx+b$

$\\ \sf\longmapsto 2=2(1)+b$

$\\ \sf\longmapsto 2=2+b$

$\\ \sf\longmapsto b=2-2=0$

Equation of the line

$\\ \sf\longmapsto y=2x$

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2 years ago

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4. A is an algebraic expression made by adding or subtracting terms.

Rasek [7]

Answer:

You have one algebraic expression. It can be simplified by adding and subtracting like terms within it.

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3 years ago

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Vera_Pavlovna [14]

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3 years ago