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masya89 [10]
2 years ago
6

Find the height of a clock tower if the angle of elevation from a horizontal point 430 m from its base is 40°.

Mathematics
2 answers:
zaharov [31]2 years ago
5 0

\\ \sf\longmapsto tan40=\dfrac{P}{430}

\\ \sf\longmapsto 0.83=\dfrac{P}{430}

\\ \sf\longmapsto P=430(0.83)

\\ \sf\longmapsto P\approx361m

  • P=Height of tower

navik [9.2K]2 years ago
4 0

Answer:

\displaystyle 361\:m.

Step-by-step explanation:

You would set your proportion up as so:

\displaystyle \frac{430}{h} = cot\:40° → 430 = hcot\: 40° → \frac{430}{cot\: 40°} = h → 360,8128414... = h \\ \\ 361 ≈ h

So, the height of the clock tower is <em>approximately</em><em> </em>361 metres.

I am joyous to assist you at any time.

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A Triangular Park ABC has sides 120 m, 80m and 50m. a gardener has to put a fence all around it and also plant grass inside. How
Vadim26 [7]

The perimeter = sum of all sides

= 120 + 80 + 50

= 250

So 250 - 3

247

Left space for gate

Now cost of fencing = Rs 20/per meter

= 247 × 20

= Rs 4,940

Now the area of the triangular park can be found using heron's formula

S = (a+b+c)/2

S = (120+80+50)/2

S = 250/2

S = 125

Now

Herons formula = √s(s-a)(s-b)(s-c)

√125(125-120)(125-80)(120-50)

√125(5)(45)(70)

√5×5×5×5×5×3×3×5×14

After Making pairs

5×5×5×3√14

375√14

Therefore 375√14m is the area of the triangular park

Must click thanks and mark brainliest

7 0
3 years ago
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Tju [1.3M]

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If the initial function is not one-to-one, then there will be more than one inverse.

So, swap the variables: y=8x−1/3x+1 becomes x=8y−1/3y+1.

Now, solve the equation x=8y−1/3y+1 for y.

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FUN QUESTIONS OF MATHETICS FOR BOREDISH PEOPLE:<br> 3x3?<br> 4x5?<br> 8x9?<br> 7x3?
PIT_PIT [208]

Answer: 3x3=9, 4x5=20, 8x9=72, and 7x3=21!

Step-by-step explanation:

5 0
2 years ago
Example 2
PIT_PIT [208]

Answer: (a) 314.2cm², (b) 157.1cm², (c) 78.55cm² (e) 6.77

Step-by-step explanation: (a)  Area of the circle with radius of 10 cm = πr²

                                                                          = 3.142 × 10 × 10

                                                                          = 3.142 × 100

                                                                          = 314.2cm²

The formula                                                       = πr²

(b)  Area of the half of a circle known as semicircle

                                                                         = πr²/2

                                                                         = 3.142 ×10 × 10/2

                                                                         = 3.142 × 50

                                                                         = 157.1cm²

The formula                                                      = πr²/2

(c)  A quarter of a circle is called quadrant

                                                            = πr²/4

                                                            = 3.142 × 10 × 10/4

                                                            = 314.2/4

                                                            = 78.55cm²

The formula is written thus = πr²/4, which implies that the circle is divided into 4 unit

(d) The conjecture about how to determine the area of the sector is

Formula of a sector = ∅/360(πr²)

<u>Information</u>

The arc  cant be 60°, therefore information incomplete.

(e) Area of the sector with the angle AOB of 60° = 24.

To find the radius of the angle, make v the subject of the formula from the formula.

Sector area = πr²∅/360°

equate formula to 24.

Therefore πr²∅/360° = 24

Multiply through by360° to make it a linear expression

It now becomes πr²∅ =24× 360°

                                                     r² = 24  x 360/π × ∅°

                                                     r² = 24 × 360° /3.142 × 60°

                                                     r² = 3,640/188.52

                                                     r² = 45.8

To find r , we take the square root of both side by applying laws of indicies

                                    Therefore r = √45 .8

                                                      r = 6.77

(f)   General formula = ∅°/360° × (πr²)

angle substended at centre by the arc = x°

assuming the radius of the circle = ycm, Therefore,  area of the sector = { ∅°/360° × πy² }

                                                     

                                                   

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3 years ago
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