$\begin{gathered} P(x)=\operatorname{\ln}\lvert4(2)+1\rvert+3(2)-(2)^2 \\ P(x)=\operatorname{\ln}\lvert9\rvert+2 \\ P(x)=4.20\text{ millions of dollars} \end{gathered}$

therefore

<h2>the answer is 4.20 million dollars</h2>

6 0

1 year ago

For a process, the average range for all samples was 5 and the process average was 25. If the sample size was 10, calculate UCL

alexira [117]

Answer:

8.885

Step-by-step explanation:

Given that :

Sample size, n = 10

The average range, Rbar for all samples = 5

The upper control limit, UCL for the R-chart is :

UCL L= D4Rbar

From the control chart constant table, D4 = 1.777

Hence,

UCL = 1.777 * 5

UCL = 8.885

The UCL for the R-chart is 8.885

7 0

3 years ago

A business bought some compact cars that cost $15,000 each, and some full–sized cars, that cost $23,000 each. A total of

stich3 [128]

It’s simple divide 372,000 by 23,000

7 0

3 years ago