Answer:
Step-by-step explanation:
Use the intercept method of graphing a straight line:
Let x = 0. We get y = 1. This is the y-intercept (0, 1).
Let y = 0. We get x = 6/11. This is the x-intercept (6/11, 0).
Plot both points and then draw a straight line through them.
The correct answer is D) 6(x+4). If we combine the like terms we get 6x+24 which is the same as 6(x+4).
The answer for this question is -6x-11
I do not have the graph that you are referencing from this question to, but I can help you get led to the right answer. If the teacher exhibits the most variable year to year performance over a 5 year span, then the graph must show unstable fluctuating of figures. Those who are least variable would have a steady line going up or down or maybe even just straight.
A histogram indicates that a normal distribution could be used as a model for the variable if the histogram is symmetric about its mean.
Given that the <span>relative frequency histogram represents the length of phone calls on george's cell phone during the month of september.
From the histogram, we can see that the histogram is left skewed, hence, the given histogram does not </span><span>indicate that a normal distribution could be used as a model for the variable.
Therefore, the answer is "No, because the histogram does not have the shape of a normal curve.
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