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2 years ago

Brian bought a computer

Mathematics

1 answer:

prisoha [69]2 years ago

4 0

Answer:

Step-by-step explanation:

100(133-380)/380=-65%

So the discount was 65%

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Find the value of x when 6-4x =7x-9x-6

Ivenika [448]

X=6
Isolate the variable by dividing each side by factors that don’t contain variable

3 0

2 years ago

Write 7:30 in two ways

Aloiza [94]

Three ways are:

In Fraction Form: $\frac{7}{30}$
In Ratio its: What you said 7:30

And

In a Percent Form Its: 0.23- %
(I got that from dividing 7 by 30.)

Hope IT helped You. :D

6 0

3 years ago

Read 2 more answers

Please help!

loris [4]

m∠B = 33° is the answer.

Step-by-step explanation:

If two triangles ΔABC and ΔMOP are similar, then their corresponding angles are congruent.

In any triangle, sum of the measure of the angles add up to 180°.

∠A+ ∠B+ ∠C = 180°

∠A ≅ ∠M

∠B ≅ ∠O

∠C ≅ ∠P

So we can add as,

∠A + ∠B+ ∠P = 180°

45° + ∠B + 102° = 180°

∠B + 147° = 180°

∠B = 180° - 147° = 33°

8 0

3 years ago

Solve -14-5y >-64 A. Y<10 B.y>-10 C. Y>10 D.y<-10

amm1812

Hello :D

Answer:

A. $Y$

Step-by-step explanation:

First, you add by 14 both sides of an equation.

-14-5y+14>-64+14

Then, simplify by equation.

-64+14=-50

-5y>-50

Multiply -1 both sides.

(-5y)(-1)<(-50)(-1)

5y<50

Divide by 5 both sides of an equation.

5y/5<50/5

Divide numbers from left to right.

50/5=10

y<10 is the correct answer.

Hope this helps you! :D

6 0

2 years ago

The region bounded by y=(3x)^(1/2), y=3x-6, y=0

Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is $y = (3x)^{\frac{1}{2} }$

⇒ $y^{2} = 3x$ ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

$y^{2} - y - 6 = 0$

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = $\int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx$

= $\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}$

= $[\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} } }{3}] - [13.5 - 18 - 6 + 12]$

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0

2 years ago