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krok68 [10]
3 years ago
11

Question 12 the length of a rectangle is three times its width. if the perimeter of the rectangle is 40 m , find its area.

Mathematics
2 answers:
earnstyle [38]3 years ago
6 0
Let the width be x.

Length = 3x

Perimeter = 40 

2*(L + W) = 40

L + W = 20

3x + x = 20

4x = 20

x = 5

Hence, 

Length = 15 m

Width = 5 m

Area = L*W = 15 * 5 = 75 sq. m
Vinil7 [7]3 years ago
5 0

Answer:

The area of the rectangle is 75 squared meters.

Step-by-step explanation:

Width of the rectangle = w

Length of the rectangle = l = 3w

Perimeter of the rectangle = P = 40 m

Perimeter of the rectangle = 2(l+w)

2(l+w)=40 m

2(3w+w)=40 m

8w=40 m

w=\frac{40 m}{8}=5 m

l=3w=3\times 5 m=15 m

The area of the rectangle ,A= l × w

A = 5 m\times 15 m = 75 m^2

The area of the rectangle is 75 squared meters.

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