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densk [106]
3 years ago
13

A large totem pole near Kalama, Washington, is 100 feet tall. On a particular day at noon it casts a 219-foot shadow. What is th

e sun's angle of elevation at that time? Round to the nearest tenth. show work

Mathematics
1 answer:
zhenek [66]3 years ago
7 0

Answer: Angle of elevation of sun at that time is 24.51° .

Step-by-step explanation:

Since we have given that

Height of a large totem pole near Kalama, Washington = 100 feet

Length of a shadow at noon = 219 foot

We need to find the angle of elevation of sun at that time .

As  we know the formula for "Tangent ":

\tan\theta=\frac{AB}{BC}\\\\\tan\theta=\frac{100}{219}\\\\\tan\theta=0.456\\\\\theta=\tan^{-1}(0.456)\\\\\theta=24.51\textdegree

Hence, Angle of elevation of sun at that time is 24.51° .

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Which of the following is either a median or an altitude?
Blizzard [7]

Answer:

PR is an altitude

QT is a median.

Step-by-step explanation:

The altitude is the perpendicular height and the median is a line from 1 vertex to the middle of the opposite side.

5 0
3 years ago
BD is the angle bisector of
AlexFokin [52]

Note: Let us consider, we need to find the m\angle ABC and m\angle DBC.

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The m\angle ABC and m\angle DBC.

Solution:

BD is the angle bisector of ABC. So,

m\angle ABD=m\angle DBC

3x=x+20

3x-x=20

2x=20

Divide both sides by 2.

x=\dfrac{20}{2}

x=10

Now,

m\angle DBC=(x+20)^\circ

m\angle DBC=(10+20)^\circ

m\angle DBC=30^\circ

And,

m\angle ABC=(3x)^\circ+(x+20)^\circ

m\angle ABC=(4x+20)^\circ

m\angle ABC=(4(10)+20)^\circ

m\angle ABC=(40+20)^\circ

m\angle ABC=60^\circ

Therefore, m\angle DBC=30^\circ,m\angle ABD=30^\circ and m\angle ABC=60^\circ.

8 0
2 years ago
|6m–54|, if m&lt;9 please help<br> write as an expression without absolute value sign
Serhud [2]

Answer:

6(m) - 54

Step-by-step explanation:

Since m < 9, you can substitute any number less than 9 to be m.

If this answer is correct, please make me Brainliest!

7 0
3 years ago
Which value completes the table?
larisa [96]
-17 -35
-3 -3
-2 0
-31 -87
17 57
7 0
3 years ago
Read 2 more answers
The five circles making up this archery target have diameters of length $2,4,6,8,$ and $10$. What is the total red area?
Sliva [168]

Answer:

A=15\pi\ units^2

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

It is given that the diameter of 5 circles making up the archery is 2,4,6,8, and 10.

To determine the total red area, we use the formula for area of the circle

A=\pi r^{2}

step 1

Find the Area of the 1st red circle

r=2/2=1\ unit ---> the radius is half the diameter

A_1=\pi (1)^{2}=\pi\ units^2

step 2

Find the Area of the 2nd white circle

r=4/2=2\ units ---> the radius is half the diameter

A_2=\pi (2)^{2}=4\pi\ units^2

step 3

Find the Area of the 3rd red circle

r=6/2=3\ units ---> the radius is half the diameter

A_3=\pi (3)^{2}=9\pi\ units^2

step 4

Find the Area of the 4th white circle

r=8/2=4\ units ---> the radius is half the diameter

A_4=\pi (4)^{2}=16\pi\ units^2

step 5

Find the Area of the 5th red circle

r=10/2=5\ units ---> the radius is half the diameter

A_5=\pi (5)^{2}=25\pi\ units^2

The total red area is given by

A=A_5-A_4+A_3-A_2+A_1

substitute

A=25\pi-16\pi+9\pi-4\pi+\pi

A=15\pi\ units^2

7 0
3 years ago
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