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Ostrovityanka [42]
3 years ago
15

A trader bought x mangoes at the rate of 4 mangoes for 10 naira five of the mangoes were bad so he sold the remaining at the rat

e of 5 mangoes for 20 naira and he made a gain of 10 naira how many mangoes did he buy ?
Mathematics
1 answer:
Ilya [14]3 years ago
3 0

Answer:

20 mangoes.

Step-by-step explanation:

Given:

Total  number of mangoes, a trader bought = x

A trader bought at the rate of 4 mangoes for 10 naira.

Five of the mangoes were bad.

He sold the remaining at the rate of 5 mangoes for 20 naira.

He made a gain of 10 naira

Question asked:

Total  number of mangoes, a trader bought = x = ?

Solution:

Unitary method

Cost price of  4 mangoes =  10 naira.

Cost price of  1 mango = \frac{10}{4}

Cost price of x mango = \frac{10}{4}\times x= \frac{5}{2} x

As 5 of the mangoes were bad and he sold the remaining mangoes, then Total number of mangoes sold =  x-5

Sale price of 5 mangoes = 20 naira

Sale price of 1 mango = \frac{20}{5}

Sale price x-5 of mango = \frac{20}{5}\times(x-5)=4(x-5)=4x-20

Now, as we know,

Gain = Sale price - cost price

10 = 4x-20 -\frac{5}{2} x\\ 10=4x-\frac{5}{2} x-20\\10=\frac{8x-5x}{2} -20

10 =\frac{3x}{2} -20

Adding both sides by 20

30=\frac{3x}{2}

Multiplying both sides by 2

60 = 3x

Dividing both sides by 3

x=20

Therefore, total number of mangoes, a trader bought is 20.

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Step-by-step explanation:

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Ninety-one percent of products come off the line within product specifications. Your quality control department selects 15 produ
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Answer:

Probability of stopping the machine when X < 9 is 0.0002

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Probability of stopping the machine when X < 12 is 0.0399

Step-by-step explanation:

There is a random binomial variable X that represents the number of units come off the line within product specifications in a review of n Bernoulli-type trials with probability of success 0.91. Therefore, the model is {15 \choose x} (0.91) ^ {x} (0.09) ^ {(15-x)}. So:

P (X < 9) = 1 - P (X \geq 9) = 1 - [{15 \choose 9} (0.91)^{9}(0.09)^{6}+...+{ 15 \choose 15}(0.91)^{15}(0.09)^{0}] = 0.0002

P (X < 10) = 1 - P (X \geq 10) = 1 - [{15 \choose 10}(0.91)^{10}(0.09)^{5}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0013

P (X < 11) = 1 - P (X \geq 11) = 1 - [{15 \choose 11}(0.91)^{11}(0.09)^{4}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0082

P (X < 12) = 1- P (X \geq 12) = 1 - [{15 \choose 12}(0.91)^{12}(0.09)^{3}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0399

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

8 0
3 years ago
45÷___=-5 what is the answer?
tatyana61 [14]

negative 8 because 45/-9 = -5

4 0
3 years ago
Read 2 more answers
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