4.5.36
1 answer:
Answer:
Step-by-step explanation:
Given function is h(t) = -16t² + 1500
a). For h(t) = 1000 feet,
1000 = -16t² + 1500
1000 - 1500 = -16t² + 1500 - 1500
-500 = -16t²
t² =
t =
t = 5.59 sec
b). For h(t) = 940 feet,
940 = -16t² + 1500
940 - 1500 = -16t² + 1500 - 1500
-16t² = -560
t² =
t =
t = 5.92 sec
c). For domain and range of the function,
When the jumper comes down to the ground,
h = 0
0 =-16t² + 1500
t² =
t =
t = 9.68 sec
Since, x-values on the graph vary from x = 0 to x = 9.68,
Domain : [0, 9.68]
Vertex of the quadratic function: (0, 1500)
Since, coefficient of the highest degree term is negative, parabola will open downwards.
Therefore, y-values of the function will vary in the interval y = 0 to y = 1500
Range: [0, 1500]
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Then, once you have plotted the open circle on -2, because all your solutions are greater than -2, draw a line on the number line (make it bold if you have to) going towards the right to show this.
To graph the solution x>-2 on a number, the first thing you need to do is to mark -2 on the number line using an open circle.
The reason you would use an open circle (like o instead of •) is because the symbols > and < represent a solution that is greater than or less than the number, but does not include it. In the case of x>-2, the solutions are all greater than than -2 but because the symbol does not state x can be -2 (if it were you would be using <span>≥</span> which states x can be any number greater than or equal to -2) all values of x are any numbers that are greater than -2 such as -1, 0, or 5.
Then, once you have plotted the open circle on -2, because all your solutions are greater than -2, draw a line on the number line (make it bold if you have to) going towards the right to show this.