Describe a strategy for converting a rate measured in one pair of units to rate measured in a diferrent pair of unit. for exampl
1 answer:
You might be interested in
Answer:
17
Step-by-step explanation:
Number of students in soccer club, n(S) = 50
Number of students in Art club, n(A) = 53
Number of students in Gaming club, n(G)
n() = 100
n() = 9
n() = 20
n() = 35
n() = 29
Formula:
n ( A ∪ B ∪ C ) = n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )
Putting the values:
100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9
100 = 112 + n(G) - 84
n(G) = 72
Number of students in gaming club only = n(G) - n() - n(
) + n(
)
= 72 - 35 - 29 + 9
= <em>17</em>
10 question of spelling words and 16 questions of vocabulary are present
<em><u>Solution:</u></em>
Let "x" be the number of spelling word questions
Let "y" be the number of vocabulary word question
<em><u>There is a total of 26 questions. Therefore, we get</u></em>
number of spelling word questions + number of vocabulary word question = 26
x + y = 26 --------- eqn 1
<em><u>There are spelling word questions that worth 2 points each and vocabulary word question worth 5 points each</u></em>
The language arts test is worth 100 points
Therefore, we frame a equation as:
number of spelling word questions x 2 + number of vocabulary word question x 5 = 100
2x + 5y = 100 --------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 1,
x = 26 - y ------- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
2(26 - y) + 5y = 100
52 - 2y + 5y = 100
3y = 100 - 52
3y = 48
<h3>y = 16</h3><em><u>Substitute y = 16 in eqn 3</u></em>
x = 26 - 16
<h3>x = 10</h3>Thus 10 question of spelling words and 16 questions of vocabulary are present