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vazorg [7]
3 years ago
12

What is nine more than a number y, if that number is 4?

Mathematics
2 answers:
IceJOKER [234]3 years ago
5 0

Answer:

13

Step-by-step explanation:

if y = 4, then 4 + 9 = 13

alisha [4.7K]3 years ago
5 0

Answer:

\huge\boxed{13}

Step-by-step explanation:

<u>The given condition is:</u>

=> y + 9

Given that y = 4

=> 4 + 9

=> 13

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how do you write the quotient (9+i) over (9-i) in standard form? I need the answer but more importantly, I need to learn how to
Scorpion4ik [409]
Since they are the conjugates of each (9-a and 9+a are conjugates, or with any number replacing 9) , we multiply it by (9+i)/(9+i) to get (9+i)^2/(9-i^2)=(81+2i+i^2)/(9-(-1))=(81-1+2i)/(10)=80/10+2i/10=8+i/5. Conjugates work because they make i into i^2 (-1) without any of the sneaky i's in the middle!
6 0
3 years ago
Ramone pays $6 for lunch and $2 for juice each day.
VMariaS [17]

Answer:

D

Step-by-step explanation:

If you were trying to find the amount of money that he would pay in 20 days, you would need to multiply the lunch and juice money by the amount of days.

6($) x 20(days) = 120

2 ($)x 20(days) = 40

So it would be 120, 40

=Answer choice D.

6 0
3 years ago
Read 2 more answers
I need help on question number 1!!!
Tju [1.3M]
B 5 makes the most sense to me
8 0
3 years ago
What is 7.7% of 50? ROUND TO THE NEAREST HUNDRETH. HELP.
Sav [38]
Your answer is 38.5. Dont forget to add units if there is any
6 0
3 years ago
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A variation on a familiar theme: A packet is received correctly by an end user with probability p. To increase the likelihood th
Leya [2.2K]

Answer:

a) X can take the values {0,1,2,3,...,n}

The probability mass function of x is defined for k copies received correctly as:

P(X=k)=\dbinom{n}{k}p^k(1-p)^{n-k}

b) N should be N=2 to ensure that with probability 0.99 at least one copy of the message is received.

Step-by-step explanation:

The variable X:number of copies received correctly by the end user can be modeled as a binomial variable, as it is a sum of n Bernoulli variables with probability p.

X can take the values {0,1,2,3,...,n}

The probability mass function of x is defined for k copies received correctly as:

P(X=k)=\dbinom{n}{k}p^k(1-p)^{n-k}

being p: the probability that a packet is received correctly by an end user, and q=1-p: the probability that a packet is not received correctly by an end user.

b) We have to calculate n so as to have a probability P(x≥1)=0.99, when p=0.9.

P(x\geq1)=1-P(x=0)=0.99\\\\\\P(x=0)=\dbinom{n}{0}p^0(1-p)^n=1*1*(1-p)^n=(1-0.9)^n=0.1^n\\\\\\P(x\geq1)=1-0.1^n=0.99\\\\0.1^n=1-0.99=0.01\\\\n\cdot ln(0.1)=ln(0.01)\\\\n=ln(0.01)/ln(0.1)=2

5 0
3 years ago
Read 2 more answers
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