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algol13
3 years ago
10

If you select a month at random from a leap year, what is the probability that the selected month will have an even number of da

ys?
Mathematics
1 answer:
trasher [3.6K]3 years ago
7 0

Answer:

5/12

Step-by-step explanation:

First, list the months by the number of days each has:

Jan:  31, Feb:  28 or 29, Mar:  31, Apr:  30, May:  31, Jun:  30, Jul:  31, Aug:  31, Sep:  30, Oct:  31, Nov:  30, Dec:  31.

How many of these 12 months have an even number of days?

Feb, Apr, Jun, Sep, Nov (assuming that we ignore Leap Year):  5 months

Then the probability that the selected month will have an even number of days is

5 months

--------------- = 5/12

12 months

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If you multiply a function and its inverse, you will will always get x back.

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Surface Area of Cylinder=2πrh+2πr2
Alex

  • Find the surface area when r is 8 inches and h is 8 inches.

\qquad A. 160π in²

\qquad B. 154π in²

\qquad C. 288π in²

\qquad D. 256π in² ☑

We are given –

\qquad ⇢Radius of cylinder , r = 8 inches

\qquad⇢ Height of cylinder, h = 8 inches.

We are asked to find surface area of the given cylinder.

Formula to find the surface cylinder given by –

\bf \star \pink{ Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2 }

Now, Substitute given values –

\sf  \twoheadrightarrow  Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 2 \pi \times 8 \times 8 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2 \pi \times 8^2 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2\pi \times 64 +2\pi \times 64

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  =128 \pi + 128\pi

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8 0
2 years ago
A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class
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We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

<u><em /></u>

<u><em>Let p = percentage of seniors who skip their classes.</em></u>

So, Null Hypothesis, H_0 : p \leq 2%   {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, H_A : p > 2%   {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

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where, \hat p = sample proportion of seniors who skipped their classes = \frac{77}{2521}

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So, <u><em>test statistics</em></u>  =  \frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }

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Therefore, we conclude that seniors skip more than 2% of their classes.

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