The equidistant point for all three, will be the "centroid" of their triangular locations
thus $\bf \textit{Centroid of a Triangle}
\begin{array}{llll}
Amy
\begin{array}{llll}
(2,3)\\
x_1,y_1
\end{array}\quad Brian
\begin{array}{llll}
(0,7)\\
x_2,y_2
\end{array}\quad Claire
\begin{array}{llll}
(-2,3)\\
x_3,y_3
\end{array}\\ \quad \\\\\\
\left(\cfrac{x_1+x_2+x_3}{3}\quad ,\cfrac{y_1+y_2+y_3}{3}\quad \right)
\end{array} 
$

6 0

2 years ago

How to find the nth term

Arte-miy333 [17]

Answer:

Write full question

I cannot understand

6 0

2 years ago

Read 2 more answers

What is the y-intercept of the line represented by y = 4x?

Brut [27]

Answer: 0

Step-by-step explanation: In order to identify the y-intercept of this equation, we want to get this equation into slope-intercept form which is more commonly known as y = mx + b form.

The problem is our equation doesn't match up quite so well with the formula y = mx + b. Our slope or m which is represented by the coefficient of the x term is clearly +4 but what is our y-intercept or b?

Well y = 4x can be thought of as y = 4x + 0 so you can see that our b or y-intercept equals 0.

5 0

3 years ago