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3 years ago

What is the circumference of a circle that has a radius of 4

Mathematics

2 answers:

rewona [7]3 years ago

6 0

I had to do this too! The answer is 25.13

Artemon [7]3 years ago

4 0

C=2pir
r=4
c=2pi4
c=8pi
aprox pi=3.14
c=25.12

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I WILL GIVE BRAINLIEST

masha68 [24]

Answer:

Part A = 64 feet

Part B = 79 feet

Step-by-step explanation:

Part A

10 × 2 = 20 = Diameter

Formula is C = π × diameter

20 × π = 62.8318530718 feet = 64 feet

Part B

25 × 2 = 50

Same formula

50 × π = 157.079632679 feet

157.079632679 ÷ 2 = 78.5398163395 feet = 79 feet

divide by 2 because it is a semi circle

Hope his helped :)

8 0

2 years ago

Every blank is a rectangle

Ray Of Light [21]

Answer:

Square

Step-by-step explanation:

6 0

2 years ago

Hi, Could anyone help me with my homework

tatiyna

Answer:

$\hookrightarrow \sf x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096$

solving steps:

$\rightarrow \sf (x + 4)^6$

$\bold{rewrite \ the \ following}$

$\rightarrow \sf (x + 4)^2 (x + 4)^2 (x + 4)^2$

$\bold {formula \ used : \sf (x+a)^2 = (x^2 + 2xa + a^2)}$

$\rightarrow \sf (x^2 + 8x+16) (x^2 + 8x+16) (x^2 + 8x+16)$

$\bold{simplify \ by \ removing \ parenthesis}$

$\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)$

$\bold{basic \ addition \ of \ integers }$

$\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)$

$\bold{remove \ parenthesis}$

$\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)$

$\bold {final \ answer:}$

$\rightarrow \sf x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096$

8 0

1 year ago

bianca has a total of 25 cents she has some nickels and pennies.How many different combinations of nickels and pennies could Bia

Hunter-Best [27]

1+1+1+1+1+5+5+5+5 is one
5+5+5+1+1+1+1+1+1+1+1+1+1 is another
5+5+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1 is three
5+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1+1 is four.

There are 4 combinations.

7 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%28%20%5Csin%5E%7B2%7D%20%28%20%5Cfrac%7B%5Cpi%7D%7B%204%20%7D%20%20-%20%20%5Calpha%20%29%20%2

guapka [62]

Step-by-step explanation:

$\sin^2 (\frac{\pi}{4} - \alpha) = \frac{1}{2}(1 - \sin 2\alpha)$

Use the identity

$\sin^2 \theta = \dfrac{1 - \cos 2\theta}{2}$

on the left side.

$\dfrac{1 - \cos [2(\frac{\pi}{4} - \alpha)]}{2} = \frac{1}{2}(1 - \sin 2\alpha)$

$\dfrac{1 - \cos (\frac{\pi}{2} - 2\alpha)}{2} = \frac{1}{2}(1 - \sin 2\alpha)$

Now use the identity

$\sin \theta = \cos(\frac{\pi}{2} - \theta)$

on the left side.

$\dfrac{1 - \sin 2\alpha}{2} = \frac{1}{2}(1 - \sin 2\alpha)$

$\frac{1}{2}(1 - \sin 2\alpha) = \frac{1}{2}(1 - \sin 2\alpha)$

4 0

2 years ago