Answer:
The probability that a randomly selected boy in secondary school can run the mile in less than 302 seconds is 0.0107
Step-by-step explanation:
Consider the provided information.
It is given that mean is 440 seconds and standard deviation is 60 seconds.
z factor for less than 302 seconds would be: 
z = (302 - 440) / 60 = -2.3
The probability of getting a z factor of less than -2.3 = 0.0107 approximately.
looking up in the z-table for a z factor of -2.3.
The probability of a student running the mile in less then 302 seconds would be 0.0107.
Hence, the probability that a randomly selected boy in secondary school can run the mile in less than 302 seconds is 0.0107
In part A, we need to solve for the total length of sides 1, 2 and 3.
Since all three sides measurements are given, we have the solution below:
Sides123 = Side 1 + Side 2 + Side 3
Sides123 = (3y² + 2y - 6) + (4y² + 3y -7) + (5y² + 4y -8)
Sides123 = 12y² + 9y - 21
This is the total length of sides 1,2 and 3 "12y² + 9y - 21"
In part B, we need to solve for the length of the fourth side and the solution is shown below:
Side 4 = Perimeter / Sides123
Side 4 = (4y³ + 18y² + 16y -26) / 12y² + 9y -21
Step-by-step explanation:
Ans: b<3. I hope this helps.
Answer:
2/100 and .02
Step-by-step explanation: