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goblinko [34]
3 years ago
9

When a = 6 and b = 22, C = 33. If c varies directly with b and inversely with a, which equation models the situation?

Mathematics
1 answer:
S_A_V [24]3 years ago
4 0

Step-by-step explanation:

C=b/a

c=kb/a

where as k is the constant

c=kb/a

we substitute

33=22k/6

crossed multiply

33*6= 22k

198=22k

we divide both sides by 22

198/22=22k/22

K=9

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Find the 70th term of the arithmetic sequence 29, 17, 5
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Answer:

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Step-by-step explanation:

70th term = a + d(n-1)

d= 29-17=12

a=29

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70th term = 29 + 12×69

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A site offers MP3 downloads with the following price structure: a $2 fixed fee for a monthly subscription plus a fee of $0.40. p
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The linear function representing the above function is

F=0.4x+2

Step-by-step explanation:

Let the total monthly cost be represented as $ F

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5 0
4 years ago
PLEASE HELP, ASAP!
Harlamova29_29 [7]
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8 0
3 years ago
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√8x^2 divided by √2x
Ghella [55]
Question: Simplify \frac{\sqrt{8x^2}}{\sqrt{2x}}.

First off, you <em>never</em> want square roots on the bottom of a fraction, so let's multiply both sides by \sqrt{2x} to get rid of it. All we have to do from there is simplify!

\frac{\sqrt{8x^2}}{\sqrt{2x}}*\frac{\sqrt{2x}}{\sqrt{2x}}=\frac{\sqrt{8x^2}*\sqrt{2x}}{2x}}=\frac{\sqrt{16x^3}}{2x}=\frac{4x\sqrt{x}}{2x}=\boxed{2\sqrt{x}}


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the temperature of a cup of coffee obeys newton's law of cooling. The initial temperature of the coffee is 150F and 1 minute lat
natka813 [3]

Answer:

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T(t) = Tₐ + (T₀ - Tₐ)*e^(k*t)

or:

\frac{dT}{dt} = -k*(T - T_a)

in the differential form.

where:

T is the temperature as a function of time

Tₐ  is the ambient temperature, in this case, 70F

T₀ is the initial temperature of the object, in this case, 150F

k is a constant, and we want to find the value of k.

Then our equation is:

T = 70F + (150F - 70F)*e^(k*t)

Now we also know that after a minute, or 60 seconds, the temperature was 135F

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We can solve this for k:

135F = 70F + 80F*e^(k*60s)

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65F =  80F*e^(k*60s)

(65/80) = e^(k*60s)

Now we can apply the Ln(x) function to both sides to get:

Ln(65/80) = Ln(e^(k*60s))

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Then the differential equation is:

\frac{dT}{dt} = -0.0035 s^-1*(T - 70F)

8 0
3 years ago
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