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Alexeev081 [22]
4 years ago
13

mrs perry shares out 30 biscuits between gemma and zak in the ration 1:4 how many biscuits does each child get

Mathematics
1 answer:
Aloiza [94]4 years ago
8 0
Gemma gets 6 Biscuits and Zak gets 24 Biscuits.
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It is given that;
Anvisha [2.4K]

Step-by-step explanation:

(i) T = { 4, 8, 12}

U = {1,2,3,4,6,8,12,24}

(iii) TUU = {1,2,3,4,6,8,12,24}

(iv) yes, because all the elements in T are also the elements in U.

3 0
3 years ago
Bubbles the fish is 4 feet below sea level. Swimmy the fish is 3 feet below sea
vampirchik [111]

Answer:

swimmy is closest to sea level

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3 years ago
I really need help plz
yanalaym [24]
The slope is m=undefined
6 0
3 years ago
I need the answer ASAP please.
kondor19780726 [428]

Answer:

Step-by-step explanation:

If 3/4 of the lot was full and the lot holds 1000 vehicles, then there are 3/4(1000) in the lot.  3/4(1000) = 750.  That means there are 750 vehicles in the lot.  If 200 cars are in the lot, then 750 - 200 = 550 trucks.

5 0
4 years ago
A random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample stand
Tpy6a [65]

Answer:

We conclude that the population mean is different from 10.5.

Step-by-step explanation:

We are given that a random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample standard deviation is 2.

<em>We have to test the claim that the population mean is 10.5.</em>

Let, NULL HYPOTHESIS, H_0 : \mu = 10.5  {means that the population mean is 10.5}

ALTERNATE HYPOTHESIS, H_a : \mu \neq 10.5  {means that the population mean is different from 10.5}

The test statistics that will be used here is One-sample t-test;

           T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean = 11

            s = sample standard deviation = 2

            \mu = population mean

            n = sample of values = 16

So, <u>test statistics</u> =  \frac{11-10.5}{\frac{2}{\sqrt{16} } } ~ t_1_5

                            = 1

<em>Now, at 0.05 significance level, t table gives a critical value of 2.131 at 15 degree of freedom. Since our test statistics is way less than the critical value of t so we have insufficient evidence to reject null hypothesis as it will not fall in the rejection region.</em>

Therefore, we conclude that the population mean is different from 10.5.

6 0
4 years ago
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