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Tom [10]
3 years ago
10

Suppose that f(5) = 1, f '(5) = 4, g(5) = −9, and g'(5) = 5. Find the following values.

Mathematics
1 answer:
stiv31 [10]3 years ago
5 0
\bf \begin{cases}
f(5)=1\qquad &f'(5)=4
\\\\
g(5)=-9\qquad &g'(x)=5
\end{cases}
\\\\

\begin{cases}
(f\cdot g)'(5)\impliedby \textit{product rule}
\\\\
\left( \frac{f}{g} \right)'(5)\impliedby \textit{quotient rule}
\end{cases}\\\\
-----------------------------\\\\
(f\cdot g)'(5)\implies f(x)\cdot g(x)\implies 
\begin{array}{llll}
f'(x)g(x)+f(x)g'(x)\\\\
x=5\\\\\
[4\cdot -9]+[1\cdot 5]
\end{array}
\\\\
-----------------------------\\\\


\bf \left( \frac{f}{g} \right)'(5)\implies 
\begin{array}{llll}
\cfrac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}\\\\
x=5\\\\
\cfrac{[4\cdot -9]-[1\cdot 5]}{(-9)^2}
\end{array}
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Step-by-step explanation:

You need to use this formula to calculate the volume of the square pyramid:

V=\frac{s^2h}{3}

Where "s" is the lenght of any side of the square base and "h" is the height of the pyramid.

Find the height with the Pythagorean Theorem:

a^2=b^2+c^2

Where "a" is the hypotenuse and "b" and "c" are the legs of the right triangle. Let be "c" the height of the pyramid.

You can identify in the figure that:

a=26mm\\\\b=\frac{23mm}{2}=11.5mm\\\\c=h

Then, you can find the height:

(26mm)^2=(11.5mm)^2+h^2\\\\h=\sqrt{(26mm)^2-(11.5mm)^2}\\\\h=23.318mm

Then, knowing that:

s=23mm\\h=23.318mm

You can calculate the volume:

 V=\frac{(23mm)^2(23.318mm)}{3}=4,111.7mm^3

3 0
3 years ago
What is $112 in 8 hours
never [62]

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n/1  

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8 0
4 years ago
Ms santos seashells into 4 row she puts 6 seashells in each row how many seachells are there altogether
kati45 [8]
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Row 3: 0 0 0 0 0 0
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3 years ago
Calculate the factorization 16w^2+48w+36=(4w+[1])^2
stiv31 [10]

Answer:

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Step-by-step explanation:

A perfect square trinomial is of the form ...

  (a + b)² = a² +2ab +b²

You have ...

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Then the factorization is ...

  16w² +48w +36 = (4w +6)²

This will be zero when x = -6/4 = -3/2.

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Step-by-step explanation:

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