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3 years ago

Ms santos seashells into 4 row she puts 6 seashells in each row how many seachells are there altogether

Mathematics

1 answer:

kati45 [8]3 years ago

3 0

4 rows and 6 seashells in each row.
Row 1: 0 0 0 0 0 0
Row 2: 0 0 0 0 0 0
Row 3: 0 0 0 0 0 0
Row 4: 0 0 0 0 0 0

You add all of them together 6+6+6+6=24
Or you could do 6x4 and your answer would be 24
So the answer to the question is 24 seashells.

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bogdanovich [222]

The answer is B

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3 years ago

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Graph the equation to solve the system y=2x-3 y=x+6

Aleksandr-060686 [28]

Y = x + 6
y = -3x + 6
put the system of linear equations into standard form
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3 years ago

The area of a rectangle is 108 m2 and its diagonal is 15 m. Find

Andre45 [30]

Answer:

47.6m.

Step by step solution:

Perimeter of a triangle = base + 2 . length____(1)

Area of a triangle = 1/2 . base . diagonal

108 = 1/2 . base . 15

multiplying both sides by 2:

216 = 15 . base

dividing both sides by 15:

base = 14.4m

But the diagonal divides the triangle into two

right angle triangles each with the same length (hypotenuse),base and diagonal(height).

Taking one right angle triangle:

And using pythagoras theorem;

length² = base² + diagonal ²

length² = 7.2² + 15²

Note: Base of each right angle triangle is 7.2 which would sum up to be 14.4 the base of the full triangle.

length² = 276.84

taking the square root of both sides:

length = 16.6m

Putting the values of the base and length into equation (1).

Perimeter of the triangle = 14.4 + 2 . 16.6

Note: We are dealing with the whole triangle

now hence the base is 14.4m.

Perimeter of the triangle = 14.4 + 33.2 = 47.6m.

6 0

3 years ago

Read 2 more answers

Faced with rising fax costs, a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail inste

Volgvan

Answer:

a) The calculated value t = 5.903 > 2.572 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is a true mean value is less than 10

b) p - value 0.00001

The p - value 0.00001 < 0.01

The result is significant at p<0.01

Step-by-step explanation:

Step(i):-

Given mean of the population = 10

Sample size 'n'= 35

Mean of the sample x⁻ = 14.44

Standard deviation of the sample 's' = 4.45

Level of significance ∝ = 0.01

Step(ii):-

Null Hypothesis H₀ : μ >10

Alternative Hypothesis : H₁ : μ < 10

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

$t = \frac{14.44-10}{\frac{4.45}{\sqrt{35} } }$

t = 5.903

Degrees of freedom = n-1 = 35-1 = 34

tabulated value t₀.₀₁,₃₄ = 2.572

The calculated value t = 5.903 > 2.572 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is a true mean value is less than 10

p- value :

p - value 0.00001

The p - value 0.00001 < 0.01

The result is significant at p<0.01

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3 years ago

An office supply store A isn’t offering copy paper for $3.00 per pack. Store B is running a special of buy two for $4.20 each an

LiRa [457]

Store B, since they are two for 4.20$ while Store A has only ONE for 3.00$ meaning let’s say we’re gonna buy two packs it would be 4.20$ for Store B and 6.00$ for Store A

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