4-3(x-y)=-8x+2
=4-3x-3y=-8x+2
=4-3x+8x-3y-2
=5x-3y+2
or
5x-3y=-2
so it will be C=5x+3y=-2
Answer:
The answer is<u> "x = 0"</u>
<em>Step-by-step explanation:</em>
<em>Step-by-step explanation: </em><em>H</em><em>ope this answer is helpful</em><em>.</em><em>.</em><em>.</em>
<em> </em><em>Make me as brainliest...</em>
Speed, S = Distance (d) / Time (t) => S= d/t => t= d/S
Let the speed of boat in still water be x mph
Resulting speed upstream = x-4 mph for a distance of 30 miles
Resulting speed downstream = x-4 mph for a distance of 50 miles
Time taken in both distances is equal.
Therefore,
30/(x-4) = 50/(x+4) => 30(x+4) = 50(x-4) => 30x+120 = 50x-200 => 120+200 = (50-30)x => 20x = 320 => x=320/20 = 16 mph
The speed of boat in still water is 16 mph.
The speed of the ball is
ds/dt = 32t
At t =1/2 s
ds/dt = 16 ft/s
The distance from the ground
50 - 16(1/2)^2 = 46 ft
The triangles formed are similar
50/46 = (30 + x)/x
x = 345 ft
50 / (50 - s) = (30 + x)/x
Taking the derivative and substituing
ds/dt = 16
and
Solve for dx/dt
