The volume of the solid objects are 612π in³ and 1566πcm³
<h3>Volume of solid object</h3>
The given objects are composite figures consisting of two shapes.
The volume of the blue figure is expressed as;
Volume = Volume of cylinder + volume of hemisphere
Volume = πr²h + 2/3πr³
Volume = πr²(h + 2/3r)
Volume = π(6)²(13+2/3(6))
Volume = 36π(13 + 4)
Volume = 612π in³
For the other object
Volume = Volume of cylinder + volume of cone
Volume = πr²h + 1/3πr²h
Volume = π(9)²(15) + 1/3π(9)²(13)
Volume= 81π (15+13/3)
Volume= 1566πcm³
Hence the volume of the solid objects are 612π in³ and 1566πcm³
Learn more on volume of composite figures here: brainly.com/question/1205683
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FIND THE NUMBER THAT MAKE EQUIVALENT FRACTION.
SOLVE LIKE THIS FOR ALL
PART - 3 --> 12
PART - 4--> 40
PART - 5 --> 6
PART - 6--> 4
PART - 7 --> 54
PART - 8 --> 12
PART - 9--> 36
PART - 10 --> 28
PART - 11--> 20
PART - 12 --> 28
PART - 13 --> 16
PART - 14 --> 20
PART - 15 --> 12
PART - 16 --> 6
PART - 17 --> 32
PART - 18--> 30
PART - 19 --> 27
PART - 20 --> 36
Answer:
It will be "q+5"
Step-by-step explanation:
When you add a number and a letter you just leave them like that. If you would to have a number multiplying a letter like "5q" and something else like "3q" when you add them together you will get "5q+3q=8q" In this case you can add them together because the number is multiplying the letter.
The two equations are
and
the first equation can be solved for x to be
next you can substitute x in the second equation
Distribute 4 to everything in the parentheses
combine like terms:
subtract 28 from both sides of the equation
divide both sides by -1.5
plug this in to the original equation of x+y=7
subtract 4 from both sides.
Final Answer: they bought 3 adult tickets and 4 student tickets
Hope this helps!
The answer is B because 11th grade is high school and Jerrod is technically in high school