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nlexa [21]
3 years ago
7

If the number of defects found is more than one standard deviation above the mean, the manufacturing facility needs to recalibra

te their machines. What is the probability that the facility needs to recalibrate their machines
Mathematics
1 answer:
Sliva [168]3 years ago
7 0

Answer:

16% probability that the facility needs to recalibrate their machines.

Step-by-step explanation:

We have to use the Empirical Rule to solve this problem.

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

What is the probability that the facility needs to recalibrate their machines?

They will have to recalibrate if the number of defects is more than one standard deviation above the mean.

We know that by the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean. The other 100-68 = 32% is more than 1 standard deviation from the mean. Since the normal distribution is symmetric, of those 32%, 16% are more than one standard deviation below the mean, and 16% are more than one standard deviation above the mean.

So there is a 16% probability that the facility needs to recalibrate their machines.

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the Following table shows alexandra's investment options over the course of three years. Her initial investment was $1,000 . wri
Y_Kistochka [10]

The pattern in the given series of amount in the account are in the form of

arithmetic and geometric progression.

  • The function for Option 1 is;  \underline{ f(n) = 1,100 + (n - 1) \cdot 100}
  • The function for Option 2 is; \underline{f(n) = 1,100 \times  1.1^{(n - 1)}}

Reasons:

The given table of values is presented as follows;

\begin{tabular}{c|c|c|c|}Number of years&1&2&3\\Option 1 (Amount in dollars)&1,100&1,200&1,300\\Option 2 (Amount in dollars)&1,100&1,210&1,331\end{array}\right]

In Option 1, the amount in dollars for each year has a common difference of d = 100

The first term, a = 1,100

Therefore;

The Option 1 can be represented as an arithmetic progression , A.P. in the

form, tₙ = a + (n - 1)·d as follows;

For the Option 1, we have;

  • The amount in dollars after <em>n</em> years, \underline{ f(n) = 1,100 + (n - 1) \cdot 100}

For Option 2, it is possible to find;

1,331 ÷ 1,210 = 1,210 ÷ 1,100 = 1.1

Therefore;

The terms in the Option 2 have a common ratio of r = 1.1

The Option 2 is a geometric progression, G.P.

The first term in Option 2 is a = 1,100

Which gives, the nth term, tₙ = a·r⁽ⁿ ⁻ ¹⁾

Therefor;

  • The function for the Option 2 is; \underline{f(n) = 1,100 \times  1.1^{(n - 1)}}

Learn more about arithmetic and geometric progression here:

brainly.com/question/8932895

brainly.com/question/22977503

4 0
3 years ago
For each of the solutions of the equations find two consecutive integers between
ale4655 [162]

Answer:

0 and 1

Step-by-step explanation:

x² = 3

take the square root of both sides

x = {-√3, √3}

x ≈ {-1.73, 1.75}

Two consecutive integers between 1.73 and 1.75

0 and 1

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tom has a large photo he wants to shrink to wallet size its width is 20 centimeters and its length is 30 centimeters if he wants
Dafna11 [192]
The length should be 7.5 centimeters
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4 years ago
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Step-by-step explanation:

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3 years ago
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Help? im confused plss!<br> Find the area of the regular polygon with the given radius or apothem
Snezhnost [94]

Answer:

  50 cm²

Step-by-step explanation:

Given that the regular polygon is a square, there are multiple ways you can jump directly to the answer. Perhaps the simplest is to use the formula for the area of a rhombus:

  A = 1/2(d1)(d2)

where d1 and d2 are the lengths of the diagonals. Here, we see that half the diagonal is 5 cm, so the area is ...

  A = (1/2)(10 cm)(10 cm) = 50 cm² . . . . area of the polygon

__

<em>Alternate solution</em>

If you want to use the radius and the number of sides in a formula, you can consider the area of each triangle formed by radii and a side. That triangle has area ...

  A = 1/2r²sin(α)

where r is the radius and α is the central angle. For an n-sided polygon, the area is the sum of n of these triangles, and the central angle is 360°/n. Then the polygon area is ...

  A = n/2·r²·sin(360°/n)

For n = 4 and r = 5 cm, the area is ...

  A = (4/2)(5 cm)²(sin(360°/4)) = 2(5 cm)²(1) = 50 cm² . . . . area of square

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<em>Additional comment</em>

The formula is somewhat different if you start with the length of the apothem. One way to find the area is using the above formula and the relation between the radius and apothem:

  r = a·sec(180°/n)

Another formula uses the apothem directly:

  A = n·a²·tan(180°/n)

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