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denis23 [38]
3 years ago
8

What is 238 divided by 3 with remainders?

Mathematics
1 answer:
saul85 [17]3 years ago
8 0
238 can be divided by 3, 79 times with a remainder of 3

Hope this helps
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Julia wrote a linear equation in standard form as –6x – 3y = 10. Arthur noticed that the equation was not written in standard fo
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When an equation is in standard form, x isn't negative so she should divide everything by a negative 1 to change it into a positive equation.
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3 years ago
Read 2 more answers
Pls send me step by step pic​
Thepotemich [5.8K]

To solve, simply do this:

(\frac{1}{2}^3)-(\frac{3}{4} )^2\\\\\frac{1}{2} *\frac{1}{2} *\frac{1}{2} *\frac{1}{2} \\\\\frac{1}{8} -(\frac{3}{4})^2\\\\\frac{1}{8}-\frac{9}{16}\\\\=\frac{-7}{16}

Then you'll get the answer, -7/16

7 0
3 years ago
Figure ABCDE was reflected across the line y = r to
marysya [2.9K]

Answer:

-2.6

Step-by-step explanation:

7 0
3 years ago
How do I solve for d if d/M-3=R
nignag [31]

Answer:

d = (R+3)(M)

Step-by-step explanation:

d/M - 3 = R

Add 3 both sides

d/M = R+3

Multiply M both sides

d = (R+3)(M)

Hope this helps!

5 0
3 years ago
Find the solutions to x2 = 24.<br> O A. x = +216<br> O B. x = 16.6<br> O C. x= 46<br> O D. x = +62
babymother [125]

Answer:

x =±2 sqrt(6)

Step-by-step explanation:

x^2 = 24

Take the square root of each side

sqrt(x^2) = sqrt(24)

x = ±sqrt(4*6)

x =±sqrt(4) sqrt(6)

x =±2 sqrt(6)

5 0
3 years ago
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