Answer:
I believe the lines are the 2nd, 4th, and 5th
Step-by-step explanation:
I don't have a clear explani=ation and you might get confused when I try to explain it :/
Answer:
Step-by-step explanation:
![\huge \sqrt[5]{ {z}^{4} {z}^{ - \frac{3}{2} } } \\ \\ = \huge \sqrt[5]{ {z}^{4 - \frac{3}{2} } } \\ \\ = \huge \sqrt[5]{ {z}^{ \frac{8 - 3}{2} } } \\ \\ = \huge \sqrt[5]{ {z}^{ \frac{5}{2} } } \\ \\ = \huge {z}^{ \frac{5}{2} \times \frac{1}{5} } \\ \\ = \huge {z}^{ \frac{1}{2} }](https://tex.z-dn.net/?f=%20%5Chuge%20%5Csqrt%5B5%5D%7B%20%7Bz%7D%5E%7B4%7D%20%7Bz%7D%5E%7B%20-%20%20%5Cfrac%7B3%7D%7B2%7D%20%7D%20%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Chuge%20%5Csqrt%5B5%5D%7B%20%7Bz%7D%5E%7B4%20-%20%20%5Cfrac%7B3%7D%7B2%7D%20%20%7D%20%20%7D%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Chuge%20%5Csqrt%5B5%5D%7B%20%7Bz%7D%5E%7B%20%5Cfrac%7B8%20-%203%7D%7B2%7D%20%20%7D%20%20%7D%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Chuge%20%5Csqrt%5B5%5D%7B%20%7Bz%7D%5E%7B%20%5Cfrac%7B5%7D%7B2%7D%20%20%7D%20%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%5Chuge%20%20%20%7Bz%7D%5E%7B%20%5Cfrac%7B5%7D%7B2%7D%20%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%3D%20%5Chuge%20%20%20%7Bz%7D%5E%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%20)
Answer:
y=3x+5
Step-by-step explanation:
The dimensions are 16 ft by 32 ft
The quadratic equation is w^2-256=0
We have given that,
Todd and his brother Robert are going to use 512 square feet of their backyard for skateboard ramps. the shape of the backyard is rectangular, with the length twice as long as the width.
<h3>What is the area of the rectangle?</h3>
The area of a rectangle is equal to
A=WL
Where L is the long side of the rectangle
W is the width side of the rectangle
in this problem we have
A=512ft^2
S0,512=LW -----> equation A
L=2W ------> equation B
substitute equation B in equation A
512=2W(W)
512=2w^2
2w^2-512=0
W^2=512/2
W=\sqrt(256)
W=16
Find the value of L
L=2W
L=2(16)
L=32ft
To learn more about rectangle visit:
brainly.com/question/25292087
#SPJ1
Answer:
2/10
Step-by-step explanation:
smart 'v'
