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3 years ago

(1-sec x)/(1-cos x) = -sec x

Mathematics

1 answer:

ra1l [238]3 years ago

7 0

We are given the trigonometric equation:

(1 - sec x) / (1 - cos x) = - sec x

Since the left side has more terms, then let us work on that side to make it exactly like the right side.

We know that sec = 1 / cos, therefore:

(1 – 1 / cos x) / (1 – cos x) = - sec x

[(cos x – 1) / cos x] / (1 – cos x) = - sec x

[- (1 – cos x) / cos x] / (1 – cos x) = - sec x

Cancelling out the term (1 – cos x):

- 1 / cos x = - sec x

<span>- sec x = - sec x

PROVEN!</span>

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Step-by-step explanation:

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3 years ago

(-2,3)(0,8) what is en equation for these points

jenyasd209 [6]

Answer:

The line equation that passes through the given points is 5x – 2y + 16 = 0

Explanation:

Given:

Two points are A(-2, 3) and B(0, 8).

To find:

The line equation that passes through the given two points.

Solution:

We know that, general equation of a line passing through two points (x1, y1), (x2, y2) is given by

$\frac{(y- y1)}{(x-x_1)}= \frac{((y_2- y_1)}{(x_2- x_1 )}$

${(y- y1)= \frac{((y_2- y_1)}{(x_2- x_1 )}\times(x-x_1)$ .............(1)

here, in our problem x1 = 0, y1 = 8, x2 = -2 and y2 = 3.

Now substitute the values in (1)

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3 years ago

Find the x-and y-intercepts of the graph of each equation<br>8. x+y=9

vampirchik [111]

Answer:

see explanation

Step-by-step explanation:

To find the x- intercept let y = 0 in the equation and solve for x

x + 0 = 9

x = 9 ← x- intercept ⇒ (9, 0 )

To find the y- intercept let x = 0 in the equation and solve for y

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y = 9 ← y- intercept ⇒ (0, 9 )

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3 years ago

Y varies directly with X and has a constant rate of change of 6. When the value of Y is 11, then the value of X could be _____.

Bogdan [553]

Answer: The correct option is (B) less than 2.

Step-by-step explanation: Given that Y varies directly with X and has a constant rate of change of 6.

We are to find the possible value of X when the value of Y is 11.

Since Y varies directly with X, so we can write

$Y\propto X\\\\\Rightarrow Y=kx~~~~~~~~~~~~~~~(i),~~~~~~~~~\textup{[where 'k' is the constant of variation]}$

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$k=6.$

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Thus, the value of X is less than 2 when Y = 11.

Option (B) is CORRECT.

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3 years ago