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fgiga [73]
3 years ago
10

28. Multiple-Concept Example 5 reviews many of the concepts that play roles in this problem. An extreme skier, starting from res

t, coasts down a mountain slope that makes an angle of 25.0 with the horizontal. The coefficient of kinetic friction between her skis and the snow is 0.200. She coasts down a distance of 10.4 m before coming to the edge of a cliff. Without slowing down, she skis off the cliff and lands downhill at a point whose vertical distance is 3.50 m below the edge. How fast is she going just before she lands
Physics
1 answer:
Maksim231197 [3]3 years ago
5 0

Answer: 7.78m/s

Explanation: As the the skier slide down the height, we assume the motion of a body, slidind down an incline plane.

Force down the plane= [email protected]

Frictional force= umg

u= coefficient of friction

Net force on skier = [email protected] umg

ma = [email protected]

a = g([email protected] - u) = 9.8 (sin 25- 0.2)

a = 9.8 × (0.4226-0.2) = 9.8 × 0.2226

a = 2.18m/s²

Using the formula V² = U² + 2aH

Where H = (10.4+ 3.5)=total height of descent before landing, U= 0.

V = √ 2 × 2.18× 13.9 = √60.604

V = 7.78m/s

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To solve this problem we will apply the concepts given by the kinematic equations of motion. For this purpose it will be necessary with the given data to obtain the deceleration. With this it will be possible again to apply one of the kinematic equations of motion that does not depend on time, but on distance, to find how far the block would slide with the quadruplicate velocity

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