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2 years ago

Chris threw a basketball a distance of 27.5 m to score and win his

Physics

1 answer:

salantis [7]2 years ago

8 0

Answer:

v₀ = 16.55 m/s

Explanation:

This motion of the ball can be modeled as a projectile motion with following data:

R = Range of Projectile = 27.5 m

θ = Launch Angle = 50°

g = acceleration due to gravity = 9.81 m/s²

v₀ = Initial Speed of Ball = ?

Therefore, using formula for range of projectile, we have:

$R = \frac{v_{0}^2\ Sin2\theta}{g}\\\\v_{0}^2 = \frac{Rg}{Sin2\theta}\\\\v_{0}^2 = \frac{(27.5\ m)(9.81\ m/s^2)}{Sin100^o}\\\\v_{0} = \sqrt{273.93\ m^2/s^2}$

v₀ = 16.55 m/s

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3 years ago

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Answer:

option a.

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3 years ago

The intensity I of light varies inversely as the square of the distance D from the source. If the intensity of illumination on a

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The intensity on a screen 20 ft from the light will be 0.125-foot candles.

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Distance is a numerical representation of the length between two objects or locations.

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Hence, the intensity on a screen 20 ft from the light will be 0.125 foot-candles

To learn more about the distance refer to the link;

brainly.com/question/26711747

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2 years ago

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3 years ago