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const2013 [10]
3 years ago
10

A beam of protons moves in a circle of radius 0.20 m. The protons move perpendicular to a 0.36-T magnetic field. (a) What is the

speed of each proton? (b) Determine the magnitude of the centripetal force that acts on each proton.
Physics
1 answer:
gregori [183]3 years ago
6 0

Answer:

a) v=6.898\times 10^{6}\ m.s^{-1} is the speed of each proton

b) F_c=3.97\times 10^{-13}\ N

Explanation:

Given:

radius of path of motion, r=0.2\ m

we know charge on protons, q=1.6\times 10^{-19}\ C

magnetic field strength, B=0.36\ T

we've mass of proton, m=1.67\times 10^{-27}\ kg

a)

From the equivalence of magnetic force and the centripetal force on the proton:

F_B=F_C

q.v.B=\frac{m.v^2}{r}

q.B=\frac{m.v}{r}

where:

v = speed of the proton

(1.6\times 10^{-19})\times 0.36=\frac{1.67\times 10^{-27}\times v}{0.2}

v=6.898\times 10^{6}\ m.s^{-1} is the speed of each proton

b)

Now the centripetal force on each proton:

F_c=m.\frac{v^2}{r}

F_c=1.67\times 10^{-27}\times \frac{(6.898\times 10^6)^2}{0.2}

F_c=3.97\times 10^{-13}\ N

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Suppose a radar gun sends out radio waves with a frequency of 2,000,000.0 Hz. The waves bounce off a moving car and return with
Igoryamba

Answer:

300,000,030m/s

Explanation:

Using the relationship between frequency and speed of a wave;

F ∝ V

F = kV

k = F/V

F1/V1 = F2/V2 = k

Let F1 be the frequency of the radio wave = 2,000,000.0Hz

V1 be the speed of light = 300,000,000m/s

F2 = frequency produced by the car = 2,000,000.2Hz

V2 be the velocity of the moving car

Substituting this values in the equation above;

2,000,000/300,000,000 = 2,000,000.2/V2

Cross multiplying

2,000,000V2 = 300,000,000×2,000,000.2

2V2 = 300×2,000,000.2

V2 = 150×2,000,000.2

V2 = 300,000,030m/s

The velocity of the car is 300,000,030m/s

6 0
3 years ago
If the atomic number of an atom is 4 and the mass number is 9, then how many electrons does it have
miskamm [114]
The atomic number of an atom says how many protons it has. This number cant change, since the atomic number is what gives elements their identities (in the periodic table, at least).
The mass number, on the other hand, says how many protons AND neutrons the atom has (so, the sum of P+ and N0). So, electrons have nothing to do with this number.
Atoms are neutrally charged, which means there has to be an equal number of positive and negative particles. The negative particles of an atom are its electrons, and since our atom has 4 protons, it must also have 4 electrons.
5 0
3 years ago
A frame hanging on a wall is held by two cables. The tension in each cable is 30 N, and the cables make an angle of 45° with the
Dimas [21]

Answer: option D) 42.4 N

The weight of the frame is balanced by the vertical component of tension.

W = T sin θ + T sin θ = 2 T sin θ

The tension in each cable is T = 30 N

Angle made by the cables with the horizontal, θ = 45°

⇒ W = 2×30 N × sin 45° = 2 × 30 N × 0.707 = 42.4 N

Hence, the weight of the frame is 42.4 N. Correct option is D.


6 0
3 years ago
Which has more kinetic energy, a 4.0 kg bowling ball moving at 1.0 m/s or a 1.0 kg
jolli1 [7]

Answer:

The kinetic energy of bocce ball is more.

Explanation:

Given that,

Mass of a bowling ball, m₁ = 4 kg

Speed of the bowling ball, v₁ = 1 m/s

Mass of bocce ball, m₂ = 1 kg

Speed of bocce ball, v₂ = 4 m/s

We need to say which has more kinetic energy.

The kinetic energy of an object is given by :

E=\dfrac{1}{2}mv^2

Kinetic energy of the bowling ball,

E_1=\dfrac{1}{2}m_1v_1^2\\\\E_1=\dfrac{1}{2}\times 4\times (1)^2\\\\E_1=2\ J

The kinetic energy of the bocce ball,

E_2=\dfrac{1}{2}m_2v_2^2\\\\E_2=\dfrac{1}{2}\times 1\times (4)^2\\\\E_2=8\ J

So, the kinetic energy of bocce ball is more than that of bowling ball.

5 0
3 years ago
A spelunker is surveying a cave. She follows a passage 140 m straight west, then 290 m in a direction 45? east of south, and the
zimovet [89]

Answer:

Magnitude of fourth displacement is approximately 95 metres,

Direction of fourth displacement is straight west.

3 0
3 years ago
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