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sweet-ann [11.9K]
3 years ago
8

An automobile has a mass of 1200 kg. What is its kinetic energy, in kJ, relative to the road when traveling at a velocity of 50

km/h? If the vehicle accelerates to 100 km/h in 15 seconds, what is the change in power required?
Physics
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

K.E = 463.04 k J

P = 23.14 Watt

Explanation:

given,

mass of automobile = 1200 kg

velocity = 50 km/h

             = 50 × 0.278

             = 13.9 m/s

kinetic energy = \dfrac{1}{2}mv^2

                        =\dfrac{1}{2}\times 1200 \times 13.9^2

        K.E = 115.93 k J

vehicle accelerated to velocity = 100 km/h

                                                    = 100 × 0.2778

                                                    = 27.78 m/s

kinetic energy = \dfrac{1}{2}mv^2

                        =\dfrac{1}{2}\times 1200 \times 27.78^2

        K.E = 463.04 k J

work done = change in kinetic energy

                   = 463.04 - 115.93

                   = 347.11 J

Power = \dfrac{work\ done}{time}

Power =\dfrac{347.11}{15}

P = 23.14 Watt

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A ski gondola is connected to the top of a hill by a steel cable of length 620 m and diameter 1.5 cm. As the gondola comes to th
xz_007 [3.2K]

Answer:

(a) 89 m/s

(b) 11000 N

Explanation:

Note that answers are given to 2 significant figures which is what we have in the values in the question.

(a) Speed is given by the ratio of distance to time. In the question, the time given was the time it took the pulse to travel the length of the cable twice. Thus, the distance travelled is twice the length of the cable.

v=\dfrac{2\times 620 \text{ m}}{14\text{ s}} = \dfrac{1240\text{ m}}{14\text{ s}}=88.571428\ldots \text{ m/s}= 89\text{ m/s}

(b) The tension, T, is given by

v =\sqrt{\dfrac{T}{\mu}}

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V = \pi \dfrac{d^{2}}{4} l

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T = \dfrac{8050\times\pi\times0.015^2}{4} \times 88.57^2

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Answer:

Explanation:

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