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adell [148]
4 years ago
15

Write as a product of 2 binomials and a monomial (factor out as much as possible from each binomial).

Mathematics
2 answers:
irakobra [83]4 years ago
8 0

Answer:

the other one is this

Step-by-step explanation:

21a(2x+3y)(2b-1)

34kurt4 years ago
6 0
The monomial factor is (4)(4) = 16.   Notice that 4 is a common factor of the first expression in parentheses, and that 4 is again a common fact. of the second expression in parentheses.  You will be left with 2 binomials, as desired.  Show your work, please.

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Algebra 2 chapter 7<br> 1-15 !!!
valentina_108 [34]
12) We first take care of the exponents: log_6 z + log_6 (x^2) - log_6 (y^3). Then we condense into a single expression: log_6 (zx^2 / y^3)
13) 5 + 8log_7 (v + 10) = 298log_7 (v + 10) = 24log_7 (v + 10) = 37^3 = v + 10343 = v + 10v = 333
14) log_5 (x^2) + log_5 (4) = 1log_5 (4x^2) = 15^1 = 4x^25/4 = x^2x = +/- sqrt(5) / 2 = +/-1.1180
*No extraneous solutions here, since the equation only uses x^2, not x.
15) -6*12^(b+7) +1 = -6-6*12^(b+7) = -712^(b+7) = 7/6
log 12^(b+7) = log(7/6)(b+7) log 12 = log (7/6)b+7 = log(7/6) / log(12) = 0.06203b = -6.9380

3 0
3 years ago
On a coordinate plane, a circle has a center at (0, 0). Point (3, 0) lies on the circle.
9966 [12]

Answer:

The correct option is;

No, the distance from (0, 0) to (2, √6) is not 3 units

Step-by-step explanation:

The given parameters of the question are as follows;

Circle center (h, k) = (0, 0)

Point on the circle (x, y) = (3, 0)

We are required to verify whether point (2, √6) lie on the circle

We note that the radius of the circle is given by the equation of the circle as follows;

Distance \, formula = \sqrt{\left (x_{2}-x_{1}  \right )^{2} + \left (y_{2}-y_{1}  \right )^{2}}

Distance² = (x - h)² + (y - k)² = r² which gives;

(3 - 0)² + (0 - 0)² = 3²

Hence r² = 3² and r = 3 units

We check the distance of the point (2, √6) from the center of the circle (0, 0) as follows;

\sqrt{\left (x_{2}-x_{1}  \right )^{2} + \left (y_{2}-y_{1}  \right )^{2}} = Distance

Therefore;

(2 - 0)² + (√6 - 0)² = 2² + √6² = 4 + 6 = 10 = √10²

\sqrt{\left (2-0 \right )^{2} + \left (\sqrt{6} -0 \right )^{2}} = 10

Which gives the distance of the point (2, √6) from the center of the circle (0, 0) = √10

Hence the distance from the circle center (0, 0) to (2, √6) is not √10 which s more than 3 units hence the point  (2, √6), does not lie on the circle.

4 0
3 years ago
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madreJ [45]

Answer:

i think b 25%

Step-by-step explanation:

but im not sure tbh

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Multiply.<br><br> 132.71 × 10²
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10*10=100
100*132.71=13271
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4 years ago
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Question 1
Ray Of Light [21]

Answer:

8, 15, 17

Step-by-step explanation:

That's a triple I remember

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3 years ago
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