Two rectangles are similar. One has a length of 11 cm and a width of 10 cm, and the other has a width of 7 cm. Find the length o
2 answers:
Answer: The correct option is
(C) 7.7 cm.
Step-by-step explanation: Given that two rectangles are similar. One has a length of 11 cm and a width of 10 cm, and the other has a width of 7 cm.
We are to find the length of the second rectangle.
Let l represents the length of the second rectangle.
We know that the corresponding sides of two similar rectangles are proportional.
So, we must have
Thus, the required length of the second rectangle is 7.7 cm.
Option (C) is CORRECT.
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Let's first rewrite it in vertex form.
Start by completing the square.
y = x² + 4x + 4 - 4 - 1
y = (x + 2)² - 5
(x + 2)² = y + 5
Now, 4a = 1; a =
So, the vertex form is (x + 2)² = 4()(y + 5)
So, we know that the vertex is at (-2, -5).
Since it's a concave up parabola, we just have to change the y-value to find the focus.
∴ F(-2, -5 +)
F(-2,
)
Start by completing the square.
y = x² + 4x + 4 - 4 - 1
y = (x + 2)² - 5
(x + 2)² = y + 5
Now, 4a = 1; a =
So, the vertex form is (x + 2)² = 4(
So, we know that the vertex is at (-2, -5).
Since it's a concave up parabola, we just have to change the y-value to find the focus.
∴ F(-2, -5 +
F(-2,