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liq [111]
2 years ago
10

Help with Another Pre Calculus Question

Mathematics
1 answer:
swat322 years ago
8 0

The last  equation h(x) = 2x+4/x+1.

<h3>What is a graph?</h3>

The pictorial representation of quantities and how the increase or decrease in one affects the other.

Analysis:

The graph cuts the x-axis and y-axis at (-2, 0) and(0, -4) respectively.

gradient of the curve = y2 - y1/x2 - x1 = -4-0/0--2 = -4/2 = -2.

The equation with a gradient equal to -2 is, h(x) = 2x+4/x+1

differentiating the equation by quotient rule,

u = 2x+4, du/dx = 2, v = x+1 dv/dx = 1

dy/dx = \frac{(x+1)(2) - (2x+4)(1)}{(x+1)^{2} } = \frac{-2}{(x+1)^{2} }

When x = -2, dy/dx = -2

In conclusion, 2x+4/x+1 is the equation for the curve above.

Learn more about parabolic curves: brainly.com/question/12896871

#SPJ1

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Michael invested a total of $14,000 in two certificates of deposit. One pays 5% interest,
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6 0
4 years ago
Suppose that 10% of all homeowners in an earthquake-prone area of California are insured against earthquake damage. Four homeown
guapka [62]

Remainder of question:

Find the probability distribution of x

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The probability distribution of X:

P(X = 0) = 0.656

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P(X= 2) = 0.0486

P(X=3) = 0.0036

P(X = 4) = 0.0001

Step-by-step explanation:

Sample size, n = 4

Random variable, X = {0, 1, 2, 3, 4}

10% (0.1) of the homeowners are insured against earthquake, p = 0.1

Proportion of homeowners who are not insured against earthquake, q = 1 - 0.1

q = 0.9

Probability distribution of x,

P(X = r) = ^nC_r *p^r q^{n-r} \\\\P(X= 0) =(^4C_0 *p^1 q^4 )\\P(X=0) = (^4C_0 *0.1^0 0.9^4 ) = 0.656\\P(X= 1)= (^4C_1 *p^1 q^3 )\\P(X=1) = (^4C_1 *0.1^1 0.9^3 ) = 0.2916\\P(X= 2)=( ^4C_2 *p^2 q^2) \\P(X=2) = (^4C_2 *0.1^2 0.9^2 ) = 0.0486\\P(X= 3) = (^4C_3 *p^3 q^3) \\ P(X=3) = (^4C_3 *0.1^3 0.9^1 ) = 0.0036\\P(X= 4) =  (^4C_4 *p^4 q^0 )\\ P(X=4) =(^4C_4 *0.1^4 0.9^0 ) = 0.0001

5 0
4 years ago
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