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liq [111]
2 years ago
10

Help with Another Pre Calculus Question

Mathematics
1 answer:
swat322 years ago
8 0

The last  equation h(x) = 2x+4/x+1.

<h3>What is a graph?</h3>

The pictorial representation of quantities and how the increase or decrease in one affects the other.

Analysis:

The graph cuts the x-axis and y-axis at (-2, 0) and(0, -4) respectively.

gradient of the curve = y2 - y1/x2 - x1 = -4-0/0--2 = -4/2 = -2.

The equation with a gradient equal to -2 is, h(x) = 2x+4/x+1

differentiating the equation by quotient rule,

u = 2x+4, du/dx = 2, v = x+1 dv/dx = 1

dy/dx = \frac{(x+1)(2) - (2x+4)(1)}{(x+1)^{2} } = \frac{-2}{(x+1)^{2} }

When x = -2, dy/dx = -2

In conclusion, 2x+4/x+1 is the equation for the curve above.

Learn more about parabolic curves: brainly.com/question/12896871

#SPJ1

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HURRYYYYYYYYY!! What is the equation of the quadratic function with a vertex at (2, 25) and an x-intercept at (7,0)?
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Answer:

y=-(x-7)(x+3)

which is none of the choices provided.

Are you sure the question is right or even the choices?

You can even write it as:

y=-(x+3)(x-7) but this is still not a choice.

Step-by-step explanation:

The vertex form of a quadratic is y=a(x-h)^2+k.

This is called vertex form because it gives you the vertex is (h,k).

We are given that (h,k)=(2,25) which makes our equation:

y=a(x-2)^2+25.

We can find the value of a by plugging in the x-intercept (7,0) for (x,y) into:

y=a(x-2)^2+25

0=a(7-2)^2+25

0=a(5)^2+25

Subtract 25 on both sides:

-25=a(5)^2

-25=a(25)

Divide both sides by 25:

\frac{-25}{25}=a

-1=a.

So the equation for the quadratic is:

y=-1(x-2)^2+25

Let's put this into factored form since all the choices are in factored form.

This will require us to multiply the (x-2)(x-2) out:

y=-1(x-2)(x-2)+25

y=-1(x^2-2x-2x+4)+25

y=-1(x^2-4x+4)+25

y=-x^2+4x-4+25

y=-x^2+4x+21

Factor out -1:

y=-(x^2-4x-21)

WE need to find two numbers that multiply to be -21 and add to be -4:

y=-(x-7)(x+3)

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