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Bumek [7]
3 years ago
5

What is the difference between 1 1/4 and 3/8

Mathematics
2 answers:
cricket20 [7]3 years ago
8 0
<span>The difference is 1/8

1/4=2/8
3/8-2/8=1/8</span>
hodyreva [135]3 years ago
6 0
1 1/4 = 5/4 = 10/8

So 10/8 - 3/8 = 7/8
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What’s the equation for<br><br> 3/9 + 2/3
Katyanochek1 [597]

Answer:

1

Step-by-step explanation:

3/9 + 2/3

Simplify the first fraction by dividing the top and bottom by 3

1/3 + 2/3

Since the denominators are the same, add the numerators

3/3

1

4 0
3 years ago
How do I find the area of this?
Temka [501]
The area is 38ft^{2} and to find this you need to use the formula length times width so 10*3.8 which equals 38.
6 0
4 years ago
Use a proof by contradiction to show that the square root of 3 is national You may use the following fact: For any integer kirke
Ierofanga [76]

Answer:

1. Let us proof that √3 is an irrational number, using <em>reductio ad absurdum</em>. Assume that \sqrt{3}=\frac{m}{n} where  m and n are non negative integers, and the fraction \frac{m}{n} is irreducible, i.e., the numbers m and n have no common factors.

Now, squaring the equality at the beginning we get that

3=\frac{m^2}{n^2} (1)

which is equivalent to 3n^2=m^2. From this we can deduce that 3 divides the number m^2, and necessarily 3 must divide m. Thus, m=3p, where p is a non negative integer.

Substituting m=3p into (1), we get

3= \frac{9p^2}{n^2}

which is equivalent to

n^2=3p^2.

Thus, 3 divides n^2 and necessarily 3 must divide n. Hence, n=3q where q is a non negative integer.

Notice that

\frac{m}{n} = \frac{3p}{3q} = \frac{p}{q}.

The above equality means that the fraction \frac{m}{n} is reducible, what contradicts our initial assumption. So, \sqrt{3} is irrational.

2. Let us prove now that the multiplication of an integer and a rational number is a rational number. So, r\in\mathbb{Q}, which is equivalent to say that r=\frac{m}{n} where  m and n are non negative integers. Also, assume that k\in\mathbb{Z}. So, we want to prove that k\cdot r\in\mathbb{Z}. Recall that an integer k can be written as

k=\frac{k}{1}.

Then,

k\cdot r = \frac{k}{1}\frac{m}{n} = \frac{mk}{n}.

Notice that the product mk is an integer. Thus, the fraction \frac{mk}{n} is a rational number. Therefore, k\cdot r\in\mathbb{Q}.

3. Let us prove by <em>reductio ad absurdum</em> that the sum of a rational number and an irrational number is an irrational number. So, we have x is irrational and p\in\mathbb{Q}.

Write q=x+p and let us suppose that q is a rational number. So, we get that

x=q-p.

But the subtraction or addition of two rational numbers is rational too. Then, the number x must be rational too, which is a clear contradiction with our hypothesis. Therefore, x+p is irrational.

7 0
4 years ago
What is the value of A? <br>5<br>5 1/3<br>6 2/3<br>7
Anna35 [415]
This is a neat little question. I don't think I've seen it before.
Step one 
=======
Find c
3^2 + 4^2 = c^2
9 + 16 = c^2
c^2 = 25
c = 5

Step 2
====
Set up your first equation for b^2
a^2 + 4^2 = b^2 from triangle XWY

Step 3
=====
Set up your second equation for b^2
25 +b^2 = (a + 3)^2 from triangle XWZ

Step 4
=====
Put the results of Step 2 into step 3 and solve
25 + a^2 + 16 = (a + 3)^2 Collect the like terms on the left.
41 + a^2 = (a + 3)^2 Expand the brackets on the right
41 + a^2 = a^2 + 6a + 9 Transfer the 9 to the left.
32 + a^2 = a^2 + 6a Subtract a^2 from both sides.
6a = 32 Divide by 6
a = 32 / 6
a = 5 2/6
a = 5 1/3
7 0
3 years ago
Read 2 more answers
PLEASEEEEEE HELPPPPP!!
DaniilM [7]

Answer:

y-b+am/m

Step-by-step explanation:

y-b=m(x-a)

y-b=MX-ma

mx=y-b+ma

x=y-b+ma/m

4 0
3 years ago
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