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2 years ago

Write a fraction with a denominater of 6 that is greater than 4/2

Mathematics

1 answer:

Strike441 [17]2 years ago

7 0

Anything over 12/6 will be greater than 4/2 such as 19/6 or 28/6

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If a baker doubles a recipe that calls for 6-2/3 cups of flour , how many cups of flour will be needed in all ?

Assoli18 [71]

13 1/3 cups needed in all

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2 years ago

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Use a single digit times a power of 10 to express the number 866,214,000,000

BartSMP [9]

Answer:

8.66214 x 10^11

Step-by-step explanation:

question may ask to round, so the answer may be simplified to 9 x 10^11

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3 years ago

Find −14(5).

erica [24]

Answer:

-14(5) = -70

9(-12) = -108

-6(-8) = 40

ab = -16(-5) = 80

6 0

2 years ago

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

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1 year ago

The two-way table shows poll results for preferred flavor of ice cream, vanilla or chocolate, and preferred topping, sprinkles o

Evgesh-ka [11]

The correct answer would be 2 over 7 or 2/7

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2 years ago

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